No. CH3COOH is a weak acid known as acetic acid or ethanoic acid.
Acetic acid (CH3COOH) is a weak acid and sodium hydroxide (NaOH) is a strong base.
The conjugate base of CH3COOH is CH3COO-. This forms when CH3COOH loses a proton (H+).
The compound is ethanoic acid, and it is not a base.
HCL is completely (or nearly 100%) ionized because it is a strong acid whereas the CH3COOH is partially ionized as it is a weak acid.
A weak acid/base will have a stronger conjugate base/acid. The conjugate acids/bases of strong bases/acids are very weak because they have no attraction to protons or hydroxides, which is why the reaction shifts all the way to the right and the Ka/b is large.
CH3COOH is a acid. It is a weak acid.
Acetic acid (CH3COOH) is a weak acid and sodium hydroxide (NaOH) is a strong base.
The conjugate base of CH3COOH is CH3COO-. This forms when CH3COOH loses a proton (H+).
The compound is ethanoic acid, and it is not a base.
Ch3cooh
HCL is completely (or nearly 100%) ionized because it is a strong acid whereas the CH3COOH is partially ionized as it is a weak acid.
A weak acid/base will have a stronger conjugate base/acid. The conjugate acids/bases of strong bases/acids are very weak because they have no attraction to protons or hydroxides, which is why the reaction shifts all the way to the right and the Ka/b is large.
It is a so called Amfolyt. Both acid and base.
There is one titratable proton in acetic acid (CH3COOH). It is the proton on the carboxyl group that can be donated in an acid-base reaction during titration.
Caustic soda is sodium hydroxide (NaOH), which is a strong base. Vinegar, a weak acid, is dilute acetic acid (CH3COOH). When combined, they undergo a neutralization reaction producing water and the salt sodium acetate (NaCH3COO). The balanced chemical equation is written below.NaOH(aq) + CH3COOH(aq) --> H2O(l) + NaCH3COO(aq)
It is a strong base.
It is a strong base.