NO!!!!
CH3COOH is the formula for the carboxylic acid Ethanoic (Acetic) Acid.
Ethanoic acid is a weak acid. it has a pH of about 3 or 4.
The IUPAC organisation have drawn up standards for organic formulae.
For Carboxylic( Weak / Fatty) acids always have the formula R-COOH .
The 'R' being the rest of the molecule.
Structurally, the 'C' has four bonds. A single bond to the 'R'. A double bond to one oxygen, and a single bond to the other oxygen , which in turn has a single bond to the hydrogen . In 2-dimension it is displayed as
R-C(=O)-O-H.
The 'H' dissociates to form 'H^(+)' the acid ion. It does not dissociate as 'O-H^(-). the hydroxide ion.
The conjugate base of CH3COOH is CH3COO-. This forms when CH3COOH loses a proton (H+).
Weak acid ; Ethanoic (Acetic) Acid Strong Base ; Sodium hydroxide Strong Acid ; Sulphuric Acid Weak Base ; Ammonia solution.
The compound is ethanoic acid, and it is not a base.
HCL is completely (or nearly 100%) ionized because it is a strong acid whereas the CH3COOH is partially ionized as it is a weak acid.
A weak acid/base will have a stronger conjugate base/acid. The conjugate acids/bases of strong bases/acids are very weak because they have no attraction to protons or hydroxides, which is why the reaction shifts all the way to the right and the Ka/b is large.
CH3COOH is a acid. It is a weak acid.
The conjugate base of CH3COOH is CH3COO-. This forms when CH3COOH loses a proton (H+).
Weak acid ; Ethanoic (Acetic) Acid Strong Base ; Sodium hydroxide Strong Acid ; Sulphuric Acid Weak Base ; Ammonia solution.
The compound is ethanoic acid, and it is not a base.
Ch3cooh
HCL is completely (or nearly 100%) ionized because it is a strong acid whereas the CH3COOH is partially ionized as it is a weak acid.
A weak acid/base will have a stronger conjugate base/acid. The conjugate acids/bases of strong bases/acids are very weak because they have no attraction to protons or hydroxides, which is why the reaction shifts all the way to the right and the Ka/b is large.
It is a so called Amfolyt. Both acid and base.
There is one titratable proton in acetic acid (CH3COOH). It is the proton on the carboxyl group that can be donated in an acid-base reaction during titration.
Caustic soda is sodium hydroxide (NaOH), which is a strong base. Vinegar, a weak acid, is dilute acetic acid (CH3COOH). When combined, they undergo a neutralization reaction producing water and the salt sodium acetate (NaCH3COO). The balanced chemical equation is written below.NaOH(aq) + CH3COOH(aq) --> H2O(l) + NaCH3COO(aq)
Acetic acid (Ethanoic acid) is a weak acid, and when reacted with a strong base like Potassium hydroxide, it establishes an equilibrium: CH3COOH + KOH <=> CH3COOK + H2O The reaction mixture contains all four products in different proportions, and as such, an acid buffer is created. When an acid is added, the CH3COO- ions (those mixed with the K+ ions) 'mop up' the H+ ions from the acid. When a base is added, the H+ ions from the CH3COOH 'mop up' the OH- ions so the pH is little affected. NB. pH=-log10(H+)
Yes, the mixture of acetic acid (CH3COOH) and sodium acetate (CH3COONa) acts as a buffer solution. This is because acetic acid is a weak acid, and sodium acetate provides its conjugate base (acetate ion, CH3COO−). Together, they can resist changes in pH when small amounts of strong acids or bases are added, maintaining a relatively stable pH in the solution.