yes
It is BASIC because, if combined with water, it produces a strong base: NaOH
No, Na+ is neutral and F- is very weakly basic, not acidic.
In the context of the question, it is none of those. It is a salt formed by the neutralization reaction between an acid and a base. In this context, the term neutral refers to an equalibrium point which is neither acid nor base, but the term does not apply to the the salt, which has no Hydrogen ion concentration (pH) to measure.
No, NaF and NaOH do not form a buffer solution together as a buffer solution requires a weak acid and its conjugate base, or a weak base and its conjugate acid. NaF is the salt of a weak acid (hydrofluoric acid) and a strong base (NaOH), so it does not act as a buffer. NaOH is a strong base and cannot act as a buffer solution by itself.
The conjugate acid of NaF is HF (hydrofluoric acid). When NaF accepts a proton, it forms HF.
It is BASIC because, if combined with water, it produces a strong base: NaOH
NaF
NaF is Sodium fluoride. It is a salt and dissolves in water. It is white in color.
NaF is a salt.
No, Na+ is neutral and F- is very weakly basic, not acidic.
In the context of the question, it is none of those. It is a salt formed by the neutralization reaction between an acid and a base. In this context, the term neutral refers to an equalibrium point which is neither acid nor base, but the term does not apply to the the salt, which has no Hydrogen ion concentration (pH) to measure.
the difference of electronegativities of sodium and fluorine is 3.1 so they form ionic bonds . the metals and non metals usually have this difference higher than 1.7 and this and higher difference is always form an ionic bond between atoms
Naf is not in the Oxford English dictionary.
No, NaF and NaOH do not form a buffer solution together as a buffer solution requires a weak acid and its conjugate base, or a weak base and its conjugate acid. NaF is the salt of a weak acid (hydrofluoric acid) and a strong base (NaOH), so it does not act as a buffer. NaOH is a strong base and cannot act as a buffer solution by itself.
To determine the number of moles of NaF in 34.2 grams of a 45.5% by mass solution, first calculate the mass of NaF in the solution. Mass of NaF = 45.5% of 34.2 grams. Then convert the mass of NaF to moles using the molar mass of NaF. Finally, divide the mass of NaF by its molar mass to get the number of moles.
The conjugate acid of NaF is HF (hydrofluoric acid). When NaF accepts a proton, it forms HF.
Naf-'t'-lee or Naf-'t'-lie