the difference of electronegativities of sodium and fluorine is 3.1 so they form ionic bonds . the metals and non metals usually have this difference higher than 1.7 and this and higher difference is always form an ionic bond between atoms
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
First recognize that NaF is the salt of a strong base (NaOH) and a weak acid (HF), so the pH will be alkaline. Next, look at the hydrolysis of NaF: NaF + H2O ---> NaOH + HF, or looking at it another way.... F^- + H2O ---> HF + OH- and here F^- acts as a base, so we need the Kb for NaF and that will be the inverse of the Ka for HF. The Ka for HF is 6.6x10^-4, so Kb = 1x10^-14/6.6x10^-4 = 1.5x10^-11. Now, Kb = [HF][OH-]/[F-] = (x)(x)/(0.89) = 1.5x10^-11 x^2 = 1.3x10^-11 x = 3.6x10^-6 = [OH-] pOH = -log 3.6x10^-6 = 5.44 pH = 8.6 (note the pH is alkaline, as expected)
To prepare a 2 ppm (parts per million) solution of sodium fluoride (NaF), dissolve 2 milligrams of NaF in enough distilled water to make a total volume of 1 liter. First, accurately weigh 2 mg of NaF using a balance, then add it to a volumetric flask or a clean container, and fill with distilled water up to the 1-liter mark. Mix thoroughly to ensure the NaF is completely dissolved.
NaF can be said as inert because +1 and -1 valencies cancells each other................ so in that way we can say , it is Neutral........
Ionic bond is used in NaF. Sodium (Na) is a metal and fluorine (F) is a non-metal, so they form an ionic bond where electrons are transferred from sodium to fluorine.
It is BASIC because, if combined with water, it produces a strong base: NaOH
NaF
NaF is Sodium fluoride. It is a salt and dissolves in water. It is white in color.
Yes, NaF is a salt composed of the elements sodium (Na) and fluorine (F). It is known as sodium fluoride.
NaF is a salt.
No, Na+ is neutral and F- is very weakly basic, not acidic.
Naf is not in the Oxford English dictionary.
No, NaF and NaOH do not form a buffer solution together as a buffer solution requires a weak acid and its conjugate base, or a weak base and its conjugate acid. NaF is the salt of a weak acid (hydrofluoric acid) and a strong base (NaOH), so it does not act as a buffer. NaOH is a strong base and cannot act as a buffer solution by itself.
To determine the number of moles of NaF in 34.2 grams of a 45.5% by mass solution, first calculate the mass of NaF in the solution. Mass of NaF = 45.5% of 34.2 grams. Then convert the mass of NaF to moles using the molar mass of NaF. Finally, divide the mass of NaF by its molar mass to get the number of moles.
The conjugate acid of NaF is HF (hydrofluoric acid). When NaF accepts a proton, it forms HF.
Naf-'t'-lee or Naf-'t'-lie
The scientific name for NaF is sodium fluoride.