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yes,it is soluble,as it makes sodium salt with NaOH.

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15y ago

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What is the pH of a 10-4 M naoh solution?

-log(10^-4 M NaOH) = 4 14 - 4 = 10 pH NaOH -----------------------


What is the pH of a 1.0 10 -6 M NaOH solution?

The pH of a 1.0 x 10^-6 M NaOH solution is approximately 11.00. This is because NaOH is a strong base that dissociates completely in solution to produce hydroxide ions, resulting in a high pH.


What is the H3O in 0048 M NaOH solution?

H3O+ concentration in a 0.048 M NaOH solution is 2.4 x 10^-12 M. This is because NaOH is a strong base that dissociates completely in water to produce Na+ and OH- ions, which react with any H3O+ ions to form water. As a result, the H3O+ concentration in such a solution is extremely low.


How many liters of naoh are in 1.3 moles of 3.42 m of naoh?

Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters


How many NaOH are needed to make 0.2 M of NaOH?

To make a 0.2 M solution of NaOH, you would need to dissolve 1 mole of NaOH in enough water to make a final volume of 1 liter. This corresponds to approximately 40 grams of NaOH.


How many ml of 0.43 m naoh will be needed to neutralize 10 ml of stomach acid if stomach acid is 0.1 m hcl?

Balanced equation first.NaOH + HCl -> NaCl + H2OAll one to one so a simple equality will do here.(X ml)(0.43 M NaOH) = (10 ml)(0.1 M HCl)0.43X = 1X = 2.3 milliliters NaOH needed--------------------------------------


How many moles of NaOH are present in 24.5 mL of 0.130 M NaOH?

Molarity = moles of solute/Liters of solution ( 24.5 mL = 0.0245 L)Rearranged,moles of solute = Liters of solution * MolarityMoles NaOH = (0.0245 L)(0.130 M NaOH)= 3.19 X 10 -3 moles NaOH==================


How many milliliters of 0.400 M NaOH are required to completely neutralize 20.00 mL of 0.200 M HCl?

To neutralize HCl with NaOH, the mole ratio is 1:1. So, the moles of HCl are 0.200 M x 0.020 L = 0.004 moles. Since NaOH and HCl react in a 1:1 ratio, we need 0.004 moles of NaOH. Using the molarity formula, we find that we need 0.010 L or 10.00 mL of 0.400 M NaOH.


A solution is prepared by mixing 360.0 mL of 0.25 M NaOH with 140.0 mL of 0.50 M NaOH and the final concentration is?

The concentration is 12,8 g/L NaOH.


WHAT IS THE MOLARITY OF 0.05 OF NAOH IN 10 ML NAOH?

To find the molarity, you need to know the amount in moles of NaOH and the volume in liters. First, convert 10 mL to liters by dividing by 1000 (10 mL = 0.01 L). Then, calculate the number of moles of NaOH using the molarity formula, Molarity = moles/volume. Given that you have 0.05 moles of NaOH and a volume of 0.01 L, the molarity would be 5 M.


How many milliliters of 6.0 M NaOH must be used to prepare 1.0 liter of 0.10 M solution?

To prepare a 0.10 M NaOH solution, you need to dilute the 6.0 M solution. You can use the formula: M1V1 = M2V2 where M1 = 6.0 M, V1 is the volume of 6.0 M NaOH needed, M2 = 0.10 M, and V2 = 1000 mL (1.0 L). By substituting the values into the formula, you can calculate the volume of the 6.0 M NaOH needed to prepare the 0.10 M solution.


How many grams of NaOH are in 750 ml 0.600 M NaOH solution?

This solution contain 26,3 g NaOH.