Yes it is. Sodium oleate is formed.
no, it is insoluble
The text is asking why a solution of oleic acid that has been weakened with water is used instead of pure oleic acid. Oleic acid is a type of fatty acid commonly found in animal and vegetable fats and oils. Diluting the solution may be necessary for certain applications to achieve a desired concentration or to prevent adverse effects.
The reaction between HCl and NaOH is a neutralization reaction, or an acid/base reaction. It isHCl + NaOH ==> NaCl + H2O
Sodium hydroxide (NaOH) react with dilute Hydrochloric Acid (HCl) to form Sodium chloride (NaCl) and water (H2O).
Dilute Nitric acid when reacted with Sodium hydroxide will produce Sodium nitrate and Water. NaOH + HNO3 = NaNO3 + H2O.
Yes it is, oleic acid (18 carbon Chain carboxylic acid) will react with the Sodium Hydroxide (NaOH) and produce a new metal salt carboxylic acid.
Yes
Dilute acid is already a solution.
no, it is insoluble
The text is asking why a solution of oleic acid that has been weakened with water is used instead of pure oleic acid. Oleic acid is a type of fatty acid commonly found in animal and vegetable fats and oils. Diluting the solution may be necessary for certain applications to achieve a desired concentration or to prevent adverse effects.
Sulfuric acid reacts violently with NaOH, producing sodium sulfate and water and lots of heat!
The reaction between HCl and NaOH is a neutralization reaction, or an acid/base reaction. It isHCl + NaOH ==> NaCl + H2O
Potassium nitrate is soluble in water, the solution is filtered and evaporated.Oleic acid is soluble in ethanol and separated by filtration and evaporation of the alcohol.
First you need the formula for the two starting ingredients. Sodium hydroxide is NaOH and Tartaric acid is HOOC--CH(OH)--CH(OH)--COOH. This can be found by looking at for example, the related link. Other searches will show that NaOH reacts with a carboxylic acid thus: -----COOH + NaOH -----> COONa +H2O in general terms. So putting all this information together we know that 2 molecules of NaOH will be needed per molecule of tartaric acid. So the final reaction equation is HOOC-CH(OH)-CH(OH)-COOH +2NaOH ----> NaOOC-CH(OH)-CH(OH)-COONa + 2H20
Sodium hydroxide (NaOH) react with dilute Hydrochloric Acid (HCl) to form Sodium chloride (NaCl) and water (H2O).
Dilute Nitric acid when reacted with Sodium hydroxide will produce Sodium nitrate and Water. NaOH + HNO3 = NaNO3 + H2O.
Oleic acid is not miscible with water.