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The word equation for the reaction of sulfuric acid and sodium hydroxide is: sulfuric acid + sodium hydroxide → sodium sulfate + water.
The reaction between sodium hydroxide and sulfuric acid produces sodium sulfate and water. Sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction to form sodium sulfate (Na2SO4) and water (H2O).
H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O. Sulfuric Acid + Sodium Hydroxide --> Sodium Sulfate + Water.
sulphuric acid
The neutralization reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) can be represented by the following equation: H2SO4 + 2NaOH → Na2SO4 + 2H2O. In this reaction, sulfuric acid reacts with sodium hydroxide to form sodium sulfate and water.
The word equation for the reaction of sulfuric acid and sodium hydroxide is: sulfuric acid + sodium hydroxide → sodium sulfate + water.
The reaction between sodium hydroxide and sulfuric acid produces sodium sulfate and water. Sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction to form sodium sulfate (Na2SO4) and water (H2O).
H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O. Sulfuric Acid + Sodium Hydroxide --> Sodium Sulfate + Water.
sulphuric acid
The neutralization reaction between sulfuric acid (H2SO4) and sodium hydroxide (NaOH) can be represented by the following equation: H2SO4 + 2NaOH → Na2SO4 + 2H2O. In this reaction, sulfuric acid reacts with sodium hydroxide to form sodium sulfate and water.
Na2SO3(aq) and H2O(l)
To neutralize the sulfuric acid completely, you need a 1:2 molar ratio of sodium hydroxide to sulfuric acid. Therefore, you would need to add twice the amount of sodium hydroxide compared to the amount of sulfuric acid, which is 40.0 mL of the sodium hydroxide solution.
The reactions of sodium hydroxide and calcium hydroxide with sulfuric acid will produce sodium sulfate and calcium sulfate respectively (water will be another product in both reactions. Sodium sulfate is soluble in water and so will remain in solution. Calcium sulfate, however, is insoluble and will precipitate as a solid.
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
A base that can neutralize sulfuric acid is sodium hydroxide (NaOH). Sulfuric acid is a strong acid, so it requires a strong base like sodium hydroxide to neutralize it, forming water and sodium sulfate as the products.
The reaction between sodium hydroxide and sulfuric acid is called a neutralization reaction. In this reaction, sodium hydroxide (a base) reacts with sulfuric acid (an acid) to form water and sodium sulfate salt.
Sodium sulfate and water are formed in the reaction between sodium hydroxide and sulfuric acid. The balanced chemical equation for this reaction is 2NaOH + H2SO4 → Na2SO4 + 2H2O.