A gram is a unit of measurement, concerning how much mass, that is, how much of something there is. You would have to weight it (or mass it) on a scale to find out.
Potassium permanganate = KMnO4 Molar mass of KMnO4 K = 1 * 39.10 g = 39.10 g Mn = 1 * 54.94 g = 54.94 g O = 4 * 16.00 g = 64.00 g Total = 158.04 g/mol 17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4 Convert the grams to kilograms. 1 kg = 1000 g 2740.41 g * (1 kg/1000 g) = 2.74041 kg Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
The molar mass for potassium iodide is 166,0028.
% by mole. There are six elements in KMnO4 only one is K so 1/6 which is 16.67% % by mass. Molar weight of K 39grams/mole. Molar weight of KMNO4 154 grams/mole so 39/154 =25%
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
Since we know the mass and molar mass, we can just insert them into this equation: n = m / M where n is the number of moles, m is the mass and M is the molar mass. I will not do the calculation for you, you should make your homework yourself (the molar mass of potassium can be found in the periodic table) :)
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
molar mass is 158.03 g/mol color is purple chemical formula is KMnO4
Potassium permanganate = KMnO4 Molar mass of KMnO4 K = 1 * 39.10 g = 39.10 g Mn = 1 * 54.94 g = 54.94 g O = 4 * 16.00 g = 64.00 g Total = 158.04 g/mol 17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4 Convert the grams to kilograms. 1 kg = 1000 g 2740.41 g * (1 kg/1000 g) = 2.74041 kg Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
The molar mass of the element potassium is 39 g/mol.
The molar mass for potassium iodide is 166,0028.
% by mole. There are six elements in KMnO4 only one is K so 1/6 which is 16.67% % by mass. Molar weight of K 39grams/mole. Molar weight of KMNO4 154 grams/mole so 39/154 =25%
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
KMnO4 is potassium permanganate.
Since we know the mass and molar mass, we can just insert them into this equation: n = m / M where n is the number of moles, m is the mass and M is the molar mass. I will not do the calculation for you, you should make your homework yourself (the molar mass of potassium can be found in the periodic table) :)
The molar mass of potassium iodide (KI) can be calculated by adding the atomic masses of potassium (K) and iodine (I). The atomic mass of potassium is approximately 39.10 g/mol, and that of iodine is about 126.90 g/mol. Therefore, the molar mass of KI is approximately 166.00 g/mol.
The valency of potassium permanganate is +7.