molar mass is 158.03 g/mol
color is purple
chemical formula is KMnO4
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
A gram is a unit of measurement, concerning how much mass, that is, how much of something there is. You would have to weight it (or mass it) on a scale to find out.
% by mole. There are six elements in KMnO4 only one is K so 1/6 which is 16.67% % by mass. Molar weight of K 39grams/mole. Molar weight of KMNO4 154 grams/mole so 39/154 =25%
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
Potassium permanganate = KMnO4 Molar mass of KMnO4 K = 1 * 39.10 g = 39.10 g Mn = 1 * 54.94 g = 54.94 g O = 4 * 16.00 g = 64.00 g Total = 158.04 g/mol 17.34 mol KMnO4 * (158.04 g/1 mol KMnO4) = 2740.41 g KMnO4 Convert the grams to kilograms. 1 kg = 1000 g 2740.41 g * (1 kg/1000 g) = 2.74041 kg Therefore, 17.34 moles of potassium permanganate is equal to about 2.74 kilograms.
Assuming that the questioner meant to write "permanganate" instead of "promangenate", the answer may be found as follows: The formula of potassium permanganate is KMnO4, showing four atoms of oxygen per formula unit. The formula unit mass of KMnO4 is 158.03; therefore, 17.7 g of potassium permanganate contains [4(17.7)/158.03](Avogadro's Number) or 2.70 X 1023 atoms of oxygen, to the justified number of significant digits.
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
To prepare a 0.01 M solution of potassium permanganate (KMnO4), first calculate the amount needed by using the formula: mass (g) = molarity (mol/L) × volume (L) × molar mass (g/mol). The molar mass of KMnO4 is approximately 158.04 g/mol, so for 1 liter of solution, you would need 1.58 grams of KMnO4. Dissolve this amount in a small volume of distilled water, then transfer the solution to a 1-liter volumetric flask and dilute to the mark with distilled water. Mix thoroughly to ensure complete dissolution.
Potassium dihydrogen phosphate, with the chemical formula KH2PO4, has one potassium atom (K) for every molecule, which has a molar mass of approximately 136.09 g/mol. Potassium constitutes about 39.1% of this molar mass, so the compound contains approximately 39.1% potassium by weight.
The percentage of iodine in potassium iodide can be calculated using the formula: (molar mass of iodine / molar mass of potassium iodide) x 100. The molar mass of iodine is approximately 126.9 g/mol, and the molar mass of potassium iodide is approximately 166 g/mol. Therefore, the percentage of iodine in potassium iodide is (126.9 / 166) x 100 = 76.5%.
The molar mass of the element potassium is 39 g/mol.