0 they are neutral
For a neutral molecule it is zero, for polyatomic ions the sum is the same as the ionic charge.
The sum of all oxidation numbers in any compound is zero. This is because atoms in a compound are electrically neutral, and the oxidation numbers reflect the charge of the atoms when they gain or lose electrons.
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
The oxidation number of carbon in Na2CO3 is +4. This is because the oxidation numbers of sodium and oxygen are always +1 and -2, respectively, and the sum of the oxidation numbers in a compound must equal zero.
In a neutral compound, the sum of oxidation numbers of all atoms will be zero. In a polyatomic ion, the sum of oxidation numbers of all atoms will be equal to the charge of the ion. The oxidation number of an element in its elemental form is zero. Fluorine always has an oxidation number of -1 in compounds. Oxygen usually has an oxidation number of -2 in compounds.
For a neutral molecule it is zero, for polyatomic ions the sum is the same as the ionic charge.
The sum of all oxidation numbers in any compound is zero. This is because atoms in a compound are electrically neutral, and the oxidation numbers reflect the charge of the atoms when they gain or lose electrons.
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
The oxidation number of carbon in Na2CO3 is +4. This is because the oxidation numbers of sodium and oxygen are always +1 and -2, respectively, and the sum of the oxidation numbers in a compound must equal zero.
In a neutral compound, the sum of oxidation numbers of all atoms will be zero. In a polyatomic ion, the sum of oxidation numbers of all atoms will be equal to the charge of the ion. The oxidation number of an element in its elemental form is zero. Fluorine always has an oxidation number of -1 in compounds. Oxygen usually has an oxidation number of -2 in compounds.
The sum of all oxidation states in a compound is equal to the overall charge of the compound. This principle is derived from the fact that the total charge of a compound must be zero for a neutral compound.
The oxidation number of sulfur in Li2SO4 is +6. This is because the oxidation numbers of Li and O are +1 and -2 respectively, and in a neutral compound the sum of all oxidation numbers must equal zero.
-1 for Carbon (in carbide) and +2 for Ca
The sum of the oxidation numbers of all carbons in C6H5CHO is equal to 0. This is because the oxidation number of carbon is -2 in CH3CHO, and there are six carbons in C6H5CHO. So, 6 * (-2) = -12. However, since the overall charge of the molecule is 0, the sum of the oxidation numbers of all carbons must be 0 to balance the charge.
To establish oxidation numbers, follow these rules: In a compound, the most electronegative element typically has a negative oxidation number (except in compounds with themselves). The sum of all oxidation numbers in a neutral compound is zero, and in a polyatomic ion, it equals the charge of the ion. Fluorine always has an oxidation number of -1 in compounds. Hydrogen usually has an oxidation number of +1, and oxygen is usually -2.
The oxidation number for hydrogen (H) is +1. Since there are 5 hydrogen atoms in H5P3O10, the total oxidation number contributed by hydrogen is +5. The sum of the oxidation numbers for all the atoms in a neutral compound is zero, so the sum of the oxidation numbers in H5P3O10 must also be zero. Therefore, the oxidation number of phosphorus (P) in H5P3O10 is +5.
The oxidation number of Na in Na2S is +1. The oxidation number of S is -2. The sum of the oxidation numbers of all atoms in a compound must equal zero.