22.5mL
whitch of the following volumes is the samllest ?
50ml of ice
a beaker
14-log2
20%
The answer will depend on the quality of the graduation.
20% or 50ml
You would need to specify the capacity of the graduated cylinder. And at that you would probably need to specify the brand. Look at the 1st figure marked on the graduation going up, then count the graduations from that downwards. eg. if the first figure is 50ml and there are 10 lines coming up to 50ml then each graduation is 5ml. (50/10)
50 ml is 50/1000 of a litre. Whether of not you use a graduated cylinder (however you choose to spell the word) is irrelevant.
Depending on how accurate you want to be you can use a variety of methods. Common methods include the following (with increasing level of accuracy) 1) graduated cylinder 2) volumetric pipette. 3) Calibrated micro-pipette (may require more than one transfer)
Firs fill a graduated cylinder that fits the rock with 50 ml. of water then recored 50ml. or what you started out with then tilt the graduated cylinder to the side and slide the rock down then record were the meniscus the water level is now then subtract 50ml. and the other number and don't forget to add your labels like ml. Hoped it helped -k
The name of the procedure to find the volume of an irregular object is calleD water displacement. You can do this by using a graduated cylinder. so say you fill the graduate up to 50ML and then you drop the object in and it is 100ML . so that tells you the volume of the object is 50ML because you subtract 100ML - 50ML = 50ML
density = mass/volume → The density of the rock is the mass of the rock divided by the difference in the volume from before the rock was dropped in and afterwards. Its units are grams/ml
whitch of the following volumes is the samllest ?
To measure a volume of liquid, laboratory instruments known as glassware are used. The commonly used glassware are burettes, pipettes, volumetric flasks and graduated cylinders.
Step 1) Fill the graduated cylinder with water to a specific volume (example: 50ml).Step 2) Drop the irregular shaped object into the graduated cylinder.Step 3) Measure the new level of the water in the graduated cylinder.Step 4) The difference in volumes in the graduated cylinder equals the volume of the irregular objectexample:original volume of water in cylinder = 50mlvolume of water in cylinder with irregular object = 55ml55ml - 50ml = volume of irregular object in the water = 5ml
You place it in water to see the volume of water it displaces. Fill a large, graduated measuring cylinder to about halfway with water (say to 50mL) Put the irregular solid in, and measure the volume it reads (solid + water). (say it reads 80mL) So the volume of the irregular solid will be: volume(solid+water) - volume(water). For example, the volume of the water was 50mL, and when the solid was added, the volume increased to 80mL. The volume of the solid would be 80mL - 50mL. So it would be 30mL.