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How many grams of oxygen are needed to react with 21.0 g of Mg?
The balanced chemical equation for the reaction between Mg and O2 is 2Mg + O2 -> 2MgO. This equation shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of O2 is 32 g/mol. Therefore, 21.0 g of Mg will react with 16.0 g of O2, which is 0.5 moles of O2.
How many moles of oxygen gas O2 needed to react with 4.00 mol of Mg?
Do you mean this reaction? 2Mg + O2 -> 2MgO 4.11 moles Mg (1 mole O2/2 mole Mg) = 2.06 moles oxygen gas consumed --------------------------------------------------
What is number of moles of oxygen gas needed to react with 4.0 moles of Mg?
The balanced chemical equation for the reaction between magnesium (Mg) and oxygen (O2) is: 2Mg + O2 -> 2MgO From the balanced equation, it is clear that 1 mole of Mg reacts with 1/2 mole of O2. Therefore, if 4.0 moles of Mg reacts, you would need 2.0 moles of O2.
How do you ensure that all the Mg would react completely with O2?
First you must find out what mass of each would react perfectly, then, if you have more than is needed of one of the reactants (if it is in excess) all of the reactant will react. Here is the calculation you need, for example, say you have 50g of each reactant. Step 1-Write out formula of reactants Mg + O2 = MgO2 1mole 1 mole Step 2 - Find the gram formula mass of reactants 1 mole Mg= 24.3 g 1 mole O2= 32 g 24.3g Mg reacts with 32g O2 Step 3 - Find amount required to react 50g Mg -- 50/32x24.3 =37.9 =37.9g Mg From that we can see that since there is 37.5g Mg and only 24.3g is needed to react completely with O2, the Mg is in excess. Substitute your starting weights in there and use that calculation, and add more than the required amount, that way you can be sure.
What is the balaced equation for mg plus o2?
The balanced equation for Mg + O2 is 2Mg + O2 → 2MgO.
How many grams of oxygen are needed to react with 21.0 g of Mg?
The balanced chemical equation for the reaction between Mg and O2 is 2Mg + O2 -> 2MgO. This equation shows that 1 mole of Mg reacts with 1 mole of O2. The molar mass of O2 is 32 g/mol. Therefore, 21.0 g of Mg will react with 16.0 g of O2, which is 0.5 moles of O2.
How many moles of oxygen gas O2 needed to react with 4.00 mol of Mg?
Do you mean this reaction? 2Mg + O2 -> 2MgO 4.11 moles Mg (1 mole O2/2 mole Mg) = 2.06 moles oxygen gas consumed --------------------------------------------------
What is number of moles of oxygen gas needed to react with 4.0 moles of Mg?
The balanced chemical equation for the reaction between magnesium (Mg) and oxygen (O2) is: 2Mg + O2 -> 2MgO From the balanced equation, it is clear that 1 mole of Mg reacts with 1/2 mole of O2. Therefore, if 4.0 moles of Mg reacts, you would need 2.0 moles of O2.
How do you ensure that all the Mg would react completely with O2?
First you must find out what mass of each would react perfectly, then, if you have more than is needed of one of the reactants (if it is in excess) all of the reactant will react. Here is the calculation you need, for example, say you have 50g of each reactant. Step 1-Write out formula of reactants Mg + O2 = MgO2 1mole 1 mole Step 2 - Find the gram formula mass of reactants 1 mole Mg= 24.3 g 1 mole O2= 32 g 24.3g Mg reacts with 32g O2 Step 3 - Find amount required to react 50g Mg -- 50/32x24.3 =37.9 =37.9g Mg From that we can see that since there is 37.5g Mg and only 24.3g is needed to react completely with O2, the Mg is in excess. Substitute your starting weights in there and use that calculation, and add more than the required amount, that way you can be sure.
What is the balaced equation for mg plus o2?
The balanced equation for Mg + O2 is 2Mg + O2 → 2MgO.
Two molecules of magnesium solid react with one molecule of oxygen gas to form two molecules of magnesium-oxide solid?
The chemical equation is:2 Mg + O2 = 2 MgO
What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
What is the word equation of magnesium react with carbon dioxide?
The chemical reaction equation would be Mg + CO2 + O -> ?.
Write a balanced symbol equation for the reaction between magnesium and oxygen to form magnesium oxide?
I'm not entirely sure but an unbalanced equation is: Mg + O2 -----> MgO
Is you start with 5 molecules of O in the reaction 2Mg O2 -----2MgO how much Mg will you need?
To react with 5 molecules of O₂, you would need the same number of molecules of Mg. This is because the balanced equation is 2Mg + O₂ → 2MgO. So, you would need 5 molecules of Mg to fully react with 5 molecules of O₂.
How do metals react with o2?
how do metals react with oxygen
How many atoms of oxygen are there on each side what chemical equation 2 Mg O2 -- 2 MgO?
There are two atoms of oxygen on each side.
