The oxidation number of antimony in Sb2O5 is +5. Each oxygen atom has an oxidation number of -2, so the total contribution of oxygen is -10. Since the compound is neutral, the sum of oxidation numbers must be zero, leading to +5 for antimony.
It would have been plus seven if possible, however the maximum is the number of valence electron of sulfur to be donated, so that is clearly +6 (six!).In H2S2O7 the oxidation number is +6
6. This is because it is a peroxide, with a structure Cr(O)(O2)2, where the nominal ligands are O2- (-2 ox.number in oxides) and O22- (-1 ox.number in peroxides) which gives the Cr an oxidation number of +6. It is sometimes called Chromium(VI) oxide peroxide.
+8.H2 has an oxidation of +1 (A total of +2)O5 has an oxidation of -2 (A total of -10).We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.Since 10 - 2 = 8, Oxidation number of S is 8.(no, it did not)Sorry,Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]Hope you got it. (yes, it did so)
The oxidation number of phosphorus in phosphorus pentoxide (P4O10) is +5. This is because each oxygen atom has an oxidation number of -2, leading to a total charge of -10 for the oxygen atoms in the compound. The sum of the oxidation numbers in a neutral compound like P4O10 is zero, so the oxidation number of phosphorus must be +5 to balance the overall charge.
The oxidation number of antimony in Sb2O5 is +5. Each oxygen atom has an oxidation number of -2, so the total contribution of oxygen is -10. Since the compound is neutral, the sum of oxidation numbers must be zero, leading to +5 for antimony.
It would have been plus seven if possible, however the maximum is the number of valence electron of sulfur to be donated, so that is clearly +6 (six!).In H2S2O7 the oxidation number is +6
Rounding numbers is easy because their are two rules to rounding numbers. 1) a </= 4 then a = 0 2) a >/= 5 then a = 10
The answer is still infinite. Infinity is not an ordinary number and does not obey the same rules as ordinary numbers.
10
spell out the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 in English then alphabetize them.
10 rules of drama
There are no set rules about rounding numbers, so when rounding numbers, mathematical rules about rounding can be used. For example, 14 would be rounded to 10, but 15 would be rounded to 20. For another example, 1144 is rounded to 1140 and 1145 is rounded to 1150.
The oxidation number of arsenic (As) in As₂O₅ is +5. Oxygen typically has an oxidation number of -2, so by using the overall charge of the compound being 0, the oxidation number of arsenic in this case can be determined as +5.
6. This is because it is a peroxide, with a structure Cr(O)(O2)2, where the nominal ligands are O2- (-2 ox.number in oxides) and O22- (-1 ox.number in peroxides) which gives the Cr an oxidation number of +6. It is sometimes called Chromium(VI) oxide peroxide.
The number of atoms in a unit is typically represented by Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole.
+8.H2 has an oxidation of +1 (A total of +2)O5 has an oxidation of -2 (A total of -10).We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.Since 10 - 2 = 8, Oxidation number of S is 8.(no, it did not)Sorry,Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]Hope you got it. (yes, it did so)