0
What else can I help you with?
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
If 1176 grams of FeS2 is allowed to react with 704 grams of O2 according to the following equation how many grams of Fe2O3 are produced?
First, balance the equation: 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. Calculate the moles of each reactant: moles FeS2 = 1176 g / molar mass of FeS2, moles O2 = 704 g / molar mass of O2. Identify the limiting reactant based on the stoichiometry of the reaction, then use stoichiometry to calculate the grams of Fe2O3 produced.
If there are 4 grams of reactant how many grams of product are produced by the chemical reaction?
The amount of product produced by a chemical reaction depends on the stoichiometry of the reaction, which is given by the coefficients in the balanced equation. Without the balanced equation or additional information, it is not possible to determine the exact amount of product produced from a specific amount of reactant. You would need to know the stoichiometry of the reaction to calculate the amount of product.
If 76 grams of Cr 2 O 3 and 27 grams of Al react to form 51 grams of Al 2 O 3 how many grams of Cr are formed?
To find the mass of Cr formed, we first need to calculate the initial moles of Cr2O3 and Al. Next, we determine the limiting reactant based on stoichiometry. Knowing Al is the limiting reactant, we calculate the theoretical yield of Al2O3 formed, and then find the amount of Cr formed based on the stoichiometry of the reaction.
How many grams of aluminum oxide can you make if you have 100 grams of aluminum combining with 50 grams of oxygen?
To find the amount of aluminum oxide that can be made, we need to determine the limiting reactant. The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. The molar mass of aluminum oxide is 101.96 g/mol. After determining the limiting reactant and doing the stoichiometry calculation, we find that 100 grams of aluminum can produce 197 grams of aluminum oxide in this reaction.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
If 1176 grams of FeS2 is allowed to react with 704 grams of O2 according to the following equation how many grams of Fe2O3 are produced?
First, balance the equation: 4FeS2 + 11O2 → 2Fe2O3 + 8SO2. Calculate the moles of each reactant: moles FeS2 = 1176 g / molar mass of FeS2, moles O2 = 704 g / molar mass of O2. Identify the limiting reactant based on the stoichiometry of the reaction, then use stoichiometry to calculate the grams of Fe2O3 produced.
If there are 4 grams of reactant how many grams of product are produced by the chemical reaction?
The amount of product produced by a chemical reaction depends on the stoichiometry of the reaction, which is given by the coefficients in the balanced equation. Without the balanced equation or additional information, it is not possible to determine the exact amount of product produced from a specific amount of reactant. You would need to know the stoichiometry of the reaction to calculate the amount of product.
If 76 grams of Cr 2 O 3 and 27 grams of Al react to form 51 grams of Al 2 O 3 how many grams of Cr are formed?
To find the mass of Cr formed, we first need to calculate the initial moles of Cr2O3 and Al. Next, we determine the limiting reactant based on stoichiometry. Knowing Al is the limiting reactant, we calculate the theoretical yield of Al2O3 formed, and then find the amount of Cr formed based on the stoichiometry of the reaction.
How many grams of aluminum oxide can you make if you have 100 grams of aluminum combining with 50 grams of oxygen?
To find the amount of aluminum oxide that can be made, we need to determine the limiting reactant. The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. The molar mass of aluminum oxide is 101.96 g/mol. After determining the limiting reactant and doing the stoichiometry calculation, we find that 100 grams of aluminum can produce 197 grams of aluminum oxide in this reaction.
What is the maximum mass of S8 that can be produced by combining 75 grams of each reactant?
The molar mass of S8 is 256 g/mol. To calculate the maximum mass of S8 that can be produced, first determine the limiting reactant by converting the masses of the reactants to moles. Then, use the stoichiometry of the reaction to find the mass of S8 produced from the limiting reactant.
Why is 160 grams of oxygen mass would be produced?
This question seems to be about the reactant side of a chemical equation. To calculate the mass of oxygen produced, you need to know the stoichiometry of the reaction. Without that information, it is not possible to determine why 160 grams of oxygen would be produced.
When a mixture of silver metal and sulfur is heated silver 1 sulfide is formed What mass of silver 1 sulfide is produced from a mixture of 5.0 g of Ag and 5.0 g of S?
This is a limiting reagent stoichiometry problem, so that means you have to run the calculations twice; once for 5 grams of silver and once for 5 grams of sulfur. When you do this, you'll find that for 5 grams of silver (and an excess of sulfur) you would get 5.68 g of product, and for 5 grams of sulfur (and an excess of silver) you would get 39.52 g of product. So, you have to go with the less of the two amounts, because that's the most you can ever produce. So the answer is 5.68 g of silver(I) sulfide, with silver being the limiting reagent.
How many grams of calcium chloride will be produced when 30.0g of calcium carbonate are combined with 12.0g of hydrochloric acid?
Based on the chemical reaction: CaCO3 + 2HCl -> CaCl2 + CO2 + H2O Calculate the limiting reactant by converting each reactant to moles and comparing the ratios. The limiting reactant is calcium carbonate. Calculate the theoretical yield of calcium chloride using the stoichiometry of the reaction.
If 108 grams of Al are allowed to completely react with 318 grams of FeO how many grams of AlO and Fe will be produced?
To calculate the amount of AlO produced, you first need to determine the limiting reactant by converting the grams of Al and FeO to moles, then comparing their molar ratios. Once you find the limiting reactant, use stoichiometry to calculate the moles of AlO produced. Finally, convert the moles of AlO to grams. The same steps can be used to find the amount of Fe produced.
In a chemical reaction 300 grams of reactant A are combined with 100 grams of reactant B . both A and B reactant to completion. how much will the product weigh?
200
How many grams of aluminum chloride could be produced from 35.5g of aluminum and 39.0g of chlorine gas?
The balanced chemical equation for the reaction is: 2Al + 3Cl₂ → 2AlCl₃ Calculate the limiting reactant: Moles of Al: 35.5g / molar mass of Al Moles of Cl₂: 39.0g / molar mass of Cl₂ Determine which reactant gives the lower amount of AlCl₃ produced. Once you know the limiting reactant, use stoichiometry to calculate the grams of AlCl₃ produced.
