NaBr contains an ionic bond, where sodium (Na) donates an electron to bromine (Br) to form Na+ and Br-. This results in the attraction between the positively charged sodium ion and the negatively charged bromine ion, forming the ionic compound NaBr.
An Ionic bond.
NaBr is ionic. There is no compound by the formula NaBr3.
NaBr forms an ionic bond. Sodium (Na) tends to lose an electron to form a cation, while bromine (Br) tends to gain an electron to form an anion. This results in the transfer of electrons from sodium to bromine, leading to the formation of an ionic bond between the two elements.
No, NaBr (sodium bromide) is an ionic compound, not a covalent compound. Ionic compounds are formed by the transfer of electrons between atoms of different electronegativities, resulting in a bond with a full transfer of electrons and an electrostatic attraction between oppositely charged ions.
Ionic bond. Sodium (Na) is a metal and bromine (Br) is a non-metal, and they bond together through the transfer of electrons from sodium to bromine, resulting in the formation of ions (Na+ and Br-).
An Ionic bond.
It is an ionic bond.
NaCl, NaOH, NaBr, KBr, KOH
NaBr is ionic. There is no compound by the formula NaBr3.
Generally the ionic bond is formed between a metal and a nonmetal (cation and anion). As an example, sodium and bromine: sodium bromide, NaBr.
NaBr forms an ionic bond. Sodium (Na) tends to lose an electron to form a cation, while bromine (Br) tends to gain an electron to form an anion. This results in the transfer of electrons from sodium to bromine, leading to the formation of an ionic bond between the two elements.
No, NaBr (sodium bromide) is an ionic compound, not a covalent compound. Ionic compounds are formed by the transfer of electrons between atoms of different electronegativities, resulting in a bond with a full transfer of electrons and an electrostatic attraction between oppositely charged ions.
Ionic bond. Sodium (Na) is a metal and bromine (Br) is a non-metal, and they bond together through the transfer of electrons from sodium to bromine, resulting in the formation of ions (Na+ and Br-).
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
The melting point of NaBr is 747 oC.
Sodium and bromine are the elements in sodium bromide (NaBr) compound.
The bond type present in the molecule CH2Cl2 is a covalent bond.