Copper Sulfate (CuSO4) will make Iron (Fe) oxidize very fast.
To find the number of moles in 22.23 g of KBr, we need to divide the given mass by the molar mass of KBr. The molar mass of KBr is 119 g/mol. Therefore, 22.23 g of KBr is equal to 0.187 moles.
CuSO4 Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O
The balanced equation for Cl2 + 2KBr -> 2Br2 + 2KCl is balanced as it conserves the number of atoms on both sides of the reaction. Two moles of KBr reacts with one mole of Cl2 to produce two moles each of Br2 and KCl.
To balance the equation K + Br₂ → KBr, you need to make sure the number of atoms of each element is the same on both sides of the equation. To balance this equation, you need to put a coefficient of 2 in front of KBr. This way, you will have 2 potassium atoms, 2 bromine atoms, and 2 KBr molecules on both sides of the equation.
When copper sulfate (CuSO4) reacts with hydrochloric acid (HCl), copper chloride (CuCl2) and sulfuric acid (H2SO4) are formed as products. The balanced chemical equation for this reaction is CuSO4 + 2HCl -> CuCl2 + H2SO4.
2 K + Br2 -> 2 Kbr
Zn + CuSO4 --> ZnSO4 + Cu
Cu + 2H2SO4 ==> CuSO4 + SO2 + 2H2OSo coefficient of CuSO4 is 1
To find the number of moles in 22.23 g of KBr, we need to divide the given mass by the molar mass of KBr. The molar mass of KBr is 119 g/mol. Therefore, 22.23 g of KBr is equal to 0.187 moles.
cuso4 +5h20 as h2so4 is acting as a dehydrating agent drawing the water out of the cuso4
CuSO4 (aq) + Fe (s) -> FeSO4 (aq) + Cu (s)
no
copper (II) sulfate is CuSO4 ; Zinc sulfate is ZnSO4 Zn + CuSO4 --> ZnSO4 + Cu
CuSO4 Cu + 2H2SO4 -> CuSO4 + SO2 + 2H2O
Na3PO4 and CuSO4
0
The balanced equation for Cl2 + 2KBr -> 2Br2 + 2KCl is balanced as it conserves the number of atoms on both sides of the reaction. Two moles of KBr reacts with one mole of Cl2 to produce two moles each of Br2 and KCl.