2 K + Br2 -> 2 Kbr
To balance the equation K + Br₂ → KBr, you need to make sure the number of atoms of each element is the same on both sides of the equation. To balance this equation, you need to put a coefficient of 2 in front of KBr. This way, you will have 2 potassium atoms, 2 bromine atoms, and 2 KBr molecules on both sides of the equation.
The balanced equation for Cl2 + 2KBr -> 2Br2 + 2KCl is balanced as it conserves the number of atoms on both sides of the reaction. Two moles of KBr reacts with one mole of Cl2 to produce two moles each of Br2 and KCl.
Yes, the equation K + Br2 = KBr is a balanced chemical equation. For example, 2 K + Br2 = 2 KBr is one and another balance chemical equation is Fe + Cl2 = FeCl3.
The correct chemical equation for the reaction is: Cl2 + 2KBr → 2KCl + Br2. The reaction involves chlorine gas (Cl2) reacting with potassium bromide (KBr) to form potassium chloride (KCl) and bromine gas (Br2).
When potassium bromide (KBr) is dissolved in water (H2O), the ions dissociate to form K+ and Br- ions. When elemental bromine (Br2) is added, the Br2 reacts with Br- ions to form bromine molecules (Br2), creating a red-brown color in the solution due to the formation of bromine.
KBr + Ch2Cl2 + HCl + HOCl you can only balance something if it reacts and produces something else. right now your chemical reaction doesnt form anything. it needs products for the reactants to be balances.
The balanced equation is: Br2 + 2Kl -> 2KBr + I2. This means there is a 2 in front of the underlined substance, KI.
2KBr + 2H2O----->2KOH + Br2 + H2(g) this is the reaction in electrolysis of KBr in aqueous solution
Potassium plus bromine will react to form potassium bromide, which is a white crystalline compound commonly used in various applications such as in photography, pharmaceuticals, and as a flame retardant.
When potassium bromide (KBr) reacts with chlorine gas (Cl2), it forms potassium chloride (KCl) and bromine (Br2). This reaction is a redox reaction, with bromide ions being oxidized to bromine gas and chlorine being reduced to chloride ions.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
The reaction 2KBr → 2K + Br2 is endothermic because heat must be supplied to break the bonds in potassium bromide (KBr) in order to form potassium (K) and bromine gas (Br2).