2HNO3 + Ca(OH)2 ==> 2H2O + Ca(NO3)2
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
The pH of a 1.45M HNO3 solution is approximately 0.14. This is because nitric acid is a strong acid that dissociates completely in water to yield H+ ions.
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
The theoretical yield of HNO3 is the maximum amount of nitric acid that can be produced in a chemical reaction based on stoichiometry and assuming 100% yield. It can be calculated by converting the given amount of reactant to moles, using the balanced equation, and then converting moles to mass of HNO3.
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
The reaction you provided is the dissociation of nitric acid (HNO3) in water. In this reaction, HNO3 donates a proton to water, forming hydronium ions (H3O+) and nitrate ions (NO3-), indicating that HNO3 is an acid.
The pH of a 1.45M HNO3 solution is approximately 0.14. This is because nitric acid is a strong acid that dissociates completely in water to yield H+ ions.
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
The balanced equation for Na + HNO3 is: 2Na + 2HNO3 -> 2NaNO3 + H2
This yields a light sensitive AgCl precipitate the above answer is not possible since there is no Silver (Ag) in either HNO3 or NaCl
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
no
This reaction doesn't exist.
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