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The reaction is exothermic.
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What does a negative deltaH tell about a reaction?
the reaction is exothermic
What does a positive H tell about a reaction?
The reaction is endothermic.
What does a positive delta H tell about reaction?
This is an endothermic chemical reaction.
What can be said about a reaction with h=-890 kj/mol and s = -0.24 kj/mol?
It can be said to be exothermic since H is negative. Also below a temp of 3708ºC, the reaction will be spontaneous because ∆G will be negative. This is from ∆G = ∆H - T∆S.
How do you know if a reaction is entropy driven enthalpy driven or driven by both enthalpy and energy?
If the ∆H is positive and the ∆S is positive, then the reaction is entropy driven. If the ∆H is negative and the ∆S is negative, then the reaction is enthalpy driven. If ∆H is positive and ∆S is negative, then the reaction is driven by neither of these. If ∆H is negative and ∆S is positive, then the reaction is driven by both of these.
What does a negative H tell you about a reaction?
yes
What does h tell about a reaction?
The reaction is exothermic.
What does a negative deltaH tell about a reaction?
the reaction is exothermic
What does a positive H tell about a reaction?
The reaction is endothermic.
What does a positive delta H tell about reaction?
This is an endothermic chemical reaction.
Are chemical reactions always spontaneous when H is negative and S is negative?
No, when H and S are both negative, the reaction will only be spontaneous below a certain temperature
What can be said about a reaction with h=-890 kj/mol and s = -0.24 kj/mol?
It can be said to be exothermic since H is negative. Also below a temp of 3708ºC, the reaction will be spontaneous because ∆G will be negative. This is from ∆G = ∆H - T∆S.
How do you know if a reaction is entropy driven enthalpy driven or driven by both enthalpy and energy?
If the ∆H is positive and the ∆S is positive, then the reaction is entropy driven. If the ∆H is negative and the ∆S is negative, then the reaction is enthalpy driven. If ∆H is positive and ∆S is negative, then the reaction is driven by neither of these. If ∆H is negative and ∆S is positive, then the reaction is driven by both of these.
How is temperature affect the spontaneity of a reaction with positive H and S?
∆G = ∆H - T∆S and ∆G has to be negative for the reaction to be spontaneous. So, ultimately the effect of temperature will depend on the value of ∆H. If ∆H is negative, and ∆S is positive, then temperature won't matter, and reaction will be spontaneous. If ∆H is positive, and ∆S is positive, then a high temperature will favor spontaneity. If ∆H is negative and ∆S is negative, then a low temperature will favor spontaneity. So, the answer to your question is the higher the temperature the more likely the reaction will occur spontaneously.
What part is in charge of automatic processes?
In science, Gibbs free energy can tell if a chemical reaction is spontaneous. It is given by the formula: G = H - TS H = enthalpy of reaction S = entropy of reaction T = temperature in Kelvin If G is negative the reaction is spontaneous. However if activation energy is high, reaction rate is slow and the reaction may take a while to progress, regardless of its spontaneity.
What condition is G for a reaction always positive?
When H and S are both positive
What conditions will a low temperature make a reaction spontaneous?
if H and S are both negative
