An oxidation number of 2 means the element has lost or gained 2 electrons in a chemical compound. The oxidation number is a measure of the element's ability to combine with other elements.
Noble gases, such as helium, neon, argon, krypton, xenon, and radon, will never have a positive oxidation number. This is because they have a full outer electron shell, making them stable and unreactive.
Lets say the oxidation number of Mn is x oxygen's oxidation number is -2 and the charge on the molecule is 1- so: 1(x) + 4(-2) = 0 x - 8 = 0 x = +8 and then you must remember that there is a negative charge to the molecule. Subtract 1. therefore oxidation number on Mn is +7
The chlorate ion is ClO3-. Some text books say that the oxidation number of the whole ion is equal to the charge, so in this cas it would be -1. However most teachers would sya that oxidation numbers only refer to atoms. So working out the oxidation numbers:- oxygen is -2, (using the rule, or if you use the he electronegativity method- gives the same answer as O is more electronegatoive than Cl) the sum of oxidation numbers of Cl and O are -1 (the charge on the ion) - I'll call the oxidation number of Cl OxCl -1 =OxCl + (3* -2)= OxCl -6 therefore OxCl = +5
+6. Working this out is tricky. Not knowing the structure, and assuming each oxygen was present as O2- you would have to say -7. This is difficult to understand as S has only 6 valence electrons. The structure is actually O3SOOSO3,(see link), 6 oxide ions (oxidation number -2) and 1 peroxide ion (overall oxidation number -2, average oxygen oxidation number of -1) . Overall the oxygen atoms contribute -14, and less the charge on the ion of -2 gives the total oxidation number of both sulfur atoms as +12, so each sulfur is +6. This is a lot more sensible. S has its maximum oxidation number of +6 as it does in SO3 and SO42-.
1. Elements on their own have an oxidation # equal to 0. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, Ca and 2Ag would have oxidation #s equal to 0.) 2. Ions in ionic compounds have an oxidation # equal to their charge. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, 2AgCl = Ag+1 and Cl-1, and CaCl2 = Ca+2 and Cl2-1.)
'Oxidation number' and oxidation state are often used interchangeably. Oxidation state is a formal way of determining the degree of oxidation of an atom or ion or molecule; for ions the oxidation number is equal to the ionic charge. In non ionic compounds the most electronegative element is assumed to "own" the electrons. So in say InP which is a semiconductor and not ionic, the oxidation state of indium is +III and P is -III. Oxidation number is a convention used in complexes. Ligands are removed from the ion with all bonding electrons. Often the oxidation number and oxidation state have the same values but calculating the the oxidation number of N in ammonia, H is removed as hydride ion, H- you get the strange looking result of nitrogen with an oxidation number of +3. In contrast the oxidation states of N and H would be calculated as -III and +1
'Oxidation number' and oxidation state are often used interchangeably. Oxidation state is a formal way of determining the degree of oxidation of an atom or ion or molecule; for ions the oxidation number is equal to the ionic charge. In non ionic compounds the most electronegative element is assumed to "own" the electrons. So in say InP which is a semiconductor and not ionic, the oxidation state of indium is +III and P is -III. Oxidation number is a convention used in complexes. Ligands are removed from the ion with all bonding electrons. Often the oxidation number and oxidation state have the same values but calculating the the oxidation number of N in ammonia, H is removed as hydride ion, H- you get the strange looking result of nitrogen with an oxidation number of +3. In contrast the oxidation states of N and H would be calculated as -III and +1
From Wikipedia (which, should you use - say - Google, would have provided a quick and cheap answer):Magnesium (pronounced /mægˈniːziəm/) is a chemical element with the symbol Mg, atomic number 12, atomic weight 24.3050 and common oxidation number +2.-matt
Noble gases, such as helium, neon, argon, krypton, xenon, and radon, will never have a positive oxidation number. This is because they have a full outer electron shell, making them stable and unreactive.
Lets say the oxidation number of Mn is x oxygen's oxidation number is -2 and the charge on the molecule is 1- so: 1(x) + 4(-2) = 0 x - 8 = 0 x = +8 and then you must remember that there is a negative charge to the molecule. Subtract 1. therefore oxidation number on Mn is +7
The atomic number is equal to the number of protons and neutrons in a neutral atom.
You mean the smallest particle of an element that still retains that element's properties. It is the atom. Even one atom of, say, carbon is still carbon. Cut it up any further and you no longer have carbon.
The chlorate ion is ClO3-. Some text books say that the oxidation number of the whole ion is equal to the charge, so in this cas it would be -1. However most teachers would sya that oxidation numbers only refer to atoms. So working out the oxidation numbers:- oxygen is -2, (using the rule, or if you use the he electronegativity method- gives the same answer as O is more electronegatoive than Cl) the sum of oxidation numbers of Cl and O are -1 (the charge on the ion) - I'll call the oxidation number of Cl OxCl -1 =OxCl + (3* -2)= OxCl -6 therefore OxCl = +5
They change with atomic number.
+6. Working this out is tricky. Not knowing the structure, and assuming each oxygen was present as O2- you would have to say -7. This is difficult to understand as S has only 6 valence electrons. The structure is actually O3SOOSO3,(see link), 6 oxide ions (oxidation number -2) and 1 peroxide ion (overall oxidation number -2, average oxygen oxidation number of -1) . Overall the oxygen atoms contribute -14, and less the charge on the ion of -2 gives the total oxidation number of both sulfur atoms as +12, so each sulfur is +6. This is a lot more sensible. S has its maximum oxidation number of +6 as it does in SO3 and SO42-.
This element (more correct in this case is isotope) doesn't suffer a radioactive disintegration.
1. Elements on their own have an oxidation # equal to 0. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, Ca and 2Ag would have oxidation #s equal to 0.) 2. Ions in ionic compounds have an oxidation # equal to their charge. (ex. in the chem equation Ca + 2AgCl --> CaCl2 +2Ag, 2AgCl = Ag+1 and Cl-1, and CaCl2 = Ca+2 and Cl2-1.)