choice 4
The electron configuration of neon determines its effective nuclear charge. Neon has a full outer electron shell, which means it has a high effective nuclear charge because the positive charge of the nucleus is not shielded by inner electrons.
The electron in the same subshell with the highest principal quantum number will experience the greatest effective nuclear charge in a many-electron atom, as it will be closest to the nucleus. Additionally, electrons in higher energy levels (with higher n values) experience less effective nuclear charge due to shielding effects from inner electrons.
Trends in the properties of elements in a group or period can be explained in terms of the periodicity of their electronic structure. Factors such as the number of electron shells, effective nuclear charge, and valence electron configuration play a key role in determining the physical and chemical properties of elements within the periodic table.
Good question. Halogens have their outer electronic configuration as ns2np5 and require only one more electron to gain a stable electronic configuration. So they have a great affinity for electrons and will accept them very easily by releasing energy. So they have the highest electron gain enthalpy.
The equation for the beta decay of 3H is: 13H --> 23He + -10e where -10e represents a negative beta particle or electron.
The electron configuration of neon determines its effective nuclear charge. Neon has a full outer electron shell, which means it has a high effective nuclear charge because the positive charge of the nucleus is not shielded by inner electrons.
The electron in the same subshell with the highest principal quantum number will experience the greatest effective nuclear charge in a many-electron atom, as it will be closest to the nucleus. Additionally, electrons in higher energy levels (with higher n values) experience less effective nuclear charge due to shielding effects from inner electrons.
The equation for the beta decay of 86Rb:3786Rb --> 3886Sr+ -10e where the -10e represents a beta particle or electron.
as you know we must first have the electron configuration to get the valence electrons. the electron configuration is: 1s2 2s2 2p6 3s2 3p6 4s2. we now have the electron configuration but we dont have the v.e. the last electron in the calcium atom are in the 4s orbital so that means that since it the only electron in the 4s orbital we will use it as a v.e. so as to get the v.e. we will subtract the shielding electrons from the nuclear charge shortly expressed by the formula below. Zeff=S-Z in this case Z will be the sum of the shielding electrons and s is the nuclear charge. Zeff=20-18 Zeff=2+ so the effective nuclear charge is 2+ or 2. hope you like it.
Trends in the properties of elements in a group or period can be explained in terms of the periodicity of their electronic structure. Factors such as the number of electron shells, effective nuclear charge, and valence electron configuration play a key role in determining the physical and chemical properties of elements within the periodic table.
It is true. The chemical properties of atoms are primarily based on the electron configuration, particularly the number of electrons in the outer or valence shell, while the nuclear properties of atoms are primarily based on the proton/neutron configuration in the nucleus.
Good question. Halogens have their outer electronic configuration as ns2np5 and require only one more electron to gain a stable electronic configuration. So they have a great affinity for electrons and will accept them very easily by releasing energy. So they have the highest electron gain enthalpy.
The equation for the beta decay of 3H is: 13H --> 23He + -10e where -10e represents a negative beta particle or electron.
Astatine has multiple energy levels, but the exact number depends on the context in which you are referring to them. In an atom, astatine can have multiple electron energy levels based on its electron configuration. In a nuclear context, astatine isotopes may have different energy levels related to their nuclear structure and decay modes.
The equation for the beta decay of 32Si is: 1432Si --> 1532P + -10e where -10e represents a negative beta particle or electron.
The electron affinity of chlorine is higher than sulfur because chlorine has a smaller atomic size and higher effective nuclear charge, resulting in stronger attraction for incoming electrons. Additionally, the electron configuration of chlorine allows for a stable octet when gaining an electron, making it energetically favorable to accept an additional electron.
Zinc has the largest ionization energy among transition metals due to its high effective nuclear charge and stable electron configuration.