0
NaOH has the higher melting point. The reason is since NaOH is an ionic compound, thus meaning that the intermolecular forces (the forces that hold the compound together) between Sodium+ and Hydroxide- are ionic - ionic forces. The charges keep them together. Ionic forces are ALOT stronger than other intermolecular forces such as dispersion, dipole-dipole, or even hydrogen bonding.
CH3OH (Methanol) has a lower melting point that Sodium Hydroxide since the intermolecular forces it entails are: Dispersion, dipole-dipole, and hydrogen bonding between Hydrogen and Oxygen. It will take LESS energy to break these attractions, than the energy required to break the attraction forces between the ionic compound NaOH.
What else can I help you with?
How is the titration of H3PO4 with NaOH performed to determine the equivalence point?
During the titration of H3PO4 with NaOH to determine the equivalence point, a known volume of H3PO4 is gradually added to a solution of NaOH until the reaction reaches a neutral point. This is detected using an indicator that changes color at the equivalence point. The volume of NaOH required to reach this point is used to calculate the concentration of H3PO4.
Reaction between sodium hydroxide and methanol?
When sodium hydroxide reacts with methanol, a neutralization reaction occurs, forming sodium methoxide and water. The balanced chemical equation for this reaction is: CH3OH + NaOH → CH3ONa + H2O
Which has higher pH value 1M HCl or 1 M NaOH solution?
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
The moles of NaOH at the equivalence point will equal the moles of acetic acid present in the solution. Therefore, using the volume and concentration of NaOH used at the equivalence point, you can calculate the moles of NaOH used. Then, based on the stoichiometry of the reaction, you can determine the moles of acetic acid, and finally, determine the concentration of the acetic acid solution.
How make 0.5ml of 2N NaOH?
To prepare 0.5 mL of 2N NaOH, you would need to dilute a higher concentration of NaOH solution. Assuming you have a 4N NaOH solution, you would mix 0.25 mL of the 4N solution with 0.25 mL of water to obtain 0.5 mL of 2N NaOH. Be cautious when handling concentrated NaOH solutions, as they are caustic and can cause skin irritation.
What is the reaction of KmNO4 with formaldehyde?
The formula of formaldehyde is CH2O. The products formed are sodium formate (HCOONa) and methanol (CH3OH). The stoichiometric equation is then X CH2O + Y NaOH --> A HCOONa + B CH3OH. Balancing the equation makes the coefficients 2 CH2O + NaOH --> HCOONa + CH3OH.
How is the titration of H3PO4 with NaOH performed to determine the equivalence point?
During the titration of H3PO4 with NaOH to determine the equivalence point, a known volume of H3PO4 is gradually added to a solution of NaOH until the reaction reaches a neutral point. This is detected using an indicator that changes color at the equivalence point. The volume of NaOH required to reach this point is used to calculate the concentration of H3PO4.
Which has higher pH value 1M HCl or 1 M NaOH solution?
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
Reaction between sodium hydroxide and methanol?
When sodium hydroxide reacts with methanol, a neutralization reaction occurs, forming sodium methoxide and water. The balanced chemical equation for this reaction is: CH3OH + NaOH → CH3ONa + H2O
20 ml of acetic acid is titrated with a solution of 0.15 M NaOH If 35 ml of NaOH are required to reach the equivalence point what is the concentration of the acetic acid solution?
The moles of NaOH at the equivalence point will equal the moles of acetic acid present in the solution. Therefore, using the volume and concentration of NaOH used at the equivalence point, you can calculate the moles of NaOH used. Then, based on the stoichiometry of the reaction, you can determine the moles of acetic acid, and finally, determine the concentration of the acetic acid solution.
How make 0.5ml of 2N NaOH?
To prepare 0.5 mL of 2N NaOH, you would need to dilute a higher concentration of NaOH solution. Assuming you have a 4N NaOH solution, you would mix 0.25 mL of the 4N solution with 0.25 mL of water to obtain 0.5 mL of 2N NaOH. Be cautious when handling concentrated NaOH solutions, as they are caustic and can cause skin irritation.
How many mL of 0.55 M NaOH would be required to reach the equivalence point for 25.0 mL of a 0.75 M solution of acetic acid?
To determine the volume of 0.55 M NaOH needed to reach the equivalence point with 25.0 mL of 0.75 M acetic acid, you need to use the stoichiometry of the reaction. Acetic acid reacts with NaOH in a 1:1 ratio, so moles of acetic acid equals moles of NaOH at the equivalence point. Calculate moles of acetic acid from its concentration and volume, equate it to moles of NaOH, and then calculate the volume of NaOH solution needed.
When NaH is added to water the hydroxide concentration increases what can you include about NaOH?
The premise of this question is incorrect. When NaOH is added to water the hydroxide concentration increases. NaOH is a base. If a substance decreases hydroxide concentration it would be an acid.
Would your calculated molarity of NaOH be too high too low or unaffected if you titrated to a dark pink color?
If you titrated to a dark pink color, it signifies that you have overshot the endpoint and added excessive NaOH. This would make your calculated molarity of NaOH too high due to the excess base added beyond the equivalence point, affecting the accuracy of the results.
20ml of acetic acid is titrated with a solutuion of 0.15 m naoh if 35 ml of naoh are required to reach the equivalence point what is the concentration of the acetic acid solution?
.26
How many Moles of NaOH equals the moles of KHP?
When titrating NaOH with KHP (potassium hydrogen phthalate), the number of moles of NaOH will be equal to the number of moles of KHP at the equivalence point. This is because the reaction is stoichiometric, with one mole of NaOH reacting with one mole of KHP.
What is nature of titration curve obtained in titration of hcl against naoh?
The titration curve obtained in titration of HCl against NaOH is a typical acid-base titration curve. It shows a gradual increase in pH at the beginning due to the addition of base (NaOH). At the equivalence point, the curve shows a sharp increase in pH since all the HCl has been neutralized. After the equivalence point, the pH continues to rise as excess NaOH is added.
