Molar mass of diazepam = 284.7 g/mol
Number of moles present in 124 g diazepam = {124 g}/{284.7 g/mol} = 0.44 mol
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The number of moles is given by :n = m / Mn = ( 4.5 g ) / ( 169.9 g / mol ) = 0.02649 moles
3,80 g Zn have 0,058 moles.
7.98 moles of Kr have 668,708 g.
Number of moles = weight (in g) / molecular weight = 6.80 / 101.961 = 0.0667 moles or 66.7 milli moles.
Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21 g/mol 124g of Mgcl2 contains moles= 95.21* 124=11806.04moles
124 grams of ethane is equal to 4,124 moles.
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The number of moles is given by :n = m / Mn = ( 4.5 g ) / ( 169.9 g / mol ) = 0.02649 moles
6675 moles Moles = weight (in g) / atomic weight = 26700 g / 4 = 6675 moles
5 moles of carbon is 60,055 g.5 moles of sodium is 114,949 g.
3,80 g Zn have 0,058 moles.
The formula is: number of moles = g Be/9,012.
7.98 moles of Kr have 668,708 g.
7.98 moles of Kr have 668,708 g.
3,99 moles of Kr have 334,35 g.
Number of moles = weight (in g) / molecular weight = 6.80 / 101.961 = 0.0667 moles or 66.7 milli moles.