Molar mass of diazepam = 284.7 g/mol
Number of moles present in 124 g diazepam = {124 g}/{284.7 g/mol} = 0.44 mol
To find the number of moles in 4.5 g of AgNO3, you first need to determine the molar mass of AgNO3 which is 169.87 g/mol. Then you can use the formula: moles = mass / molar mass. Therefore, moles = 4.5 g / 169.87 g/mol ≈ 0.0265 moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
To find the number of moles of argon in 24.7 g, you need to divide the mass of the sample by the molar mass of argon (39.95 g/mol). Therefore, 24.7 g of argon is equal to 0.62 moles (24.7 g ÷ 39.95 g/mol = 0.62 mol).
To find the number of moles of argon in 37.9 g, you need to use the molar mass of argon, which is 39.95 g/mol. Divide the given mass by the molar mass to get the number of moles. So, 37.9 g / 39.95 g/mol = 0.95 moles of argon.
Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21 g/mol 124g of Mgcl2 contains moles= 95.21* 124=11806.04moles
124 grams of ethane is equal to 4,124 moles.
To find the number of moles in 4.5 g of AgNO3, you first need to determine the molar mass of AgNO3 which is 169.87 g/mol. Then you can use the formula: moles = mass / molar mass. Therefore, moles = 4.5 g / 169.87 g/mol ≈ 0.0265 moles.
To find the amount in moles of tantalum (Ta) in 26.1 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of tantalum is approximately 180.95 g/mol. Thus, moles of Ta = 26.1 g / 180.95 g/mol ≈ 0.144 moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
5 moles of carbon is 60,055 g.5 moles of sodium is 114,949 g.
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
3,99 moles of Kr have 334,35 g.
7.98 moles of Kr have 668,708 g.
The formula is: number of moles = g Be/9,012.
To find the number of moles of argon in 24.7 g, you need to divide the mass of the sample by the molar mass of argon (39.95 g/mol). Therefore, 24.7 g of argon is equal to 0.62 moles (24.7 g ÷ 39.95 g/mol = 0.62 mol).