I suppose that it stands for two molecules of hydrochloric acid.
Oh, dude, it's simple! To make 2M HCl in 100ml from 36% HCl, you'd need to dilute the 36% HCl with water. Just mix 5.56ml of 36% HCl with 94.44ml of water, and voila, you've got yourself some 2M HCl. It's like making a fancy cocktail, but with chemicals!
The pH of a 2M HCl solution is around 0. This is because HCl is a strong acid that dissociates completely in water to produce H+ ions, leading to a highly acidic solution.
To prepare a 2M HCl solution from liquid HCl, you need to calculate the volume of the liquid HCl required. Since the concentration of the stock solution is not provided, you can use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired final concentration (2M), and V2 is the final volume of the solution (usually 1 liter). Once you calculate the volume needed, carefully dilute the liquid HCl with distilled water in a volumetric flask to reach a total volume of 1 liter. Be cautious when handling concentrated HCl as it is corrosive and can cause burns.
To calculate the number of moles of HCl, you need to use the formula: moles = Molarity (M) x Volume (L) Convert 230 cm^3 to liters: 230 cm^3 ÷ 1000 = 0.23 L Now, plug in the values: moles = 2M x 0.23 L = 0.46 moles of HCl in 230 cm^3 of 2M hydrochloric acid.
they both are same as HCl is a monobasic acid.>>>Not exactly. N stands for normal and M stands for mole. Knowing that, read this article to know the difference:http://answers.yahoo.com/question/index?qid=20070625100319AALNjoW
Oh, dude, it's simple! To make 2M HCl in 100ml from 36% HCl, you'd need to dilute the 36% HCl with water. Just mix 5.56ml of 36% HCl with 94.44ml of water, and voila, you've got yourself some 2M HCl. It's like making a fancy cocktail, but with chemicals!
The pH of a 2M HCl solution is around 0. This is because HCl is a strong acid that dissociates completely in water to produce H+ ions, leading to a highly acidic solution.
To prepare a 2M HCl solution from liquid HCl, you need to calculate the volume of the liquid HCl required. Since the concentration of the stock solution is not provided, you can use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired final concentration (2M), and V2 is the final volume of the solution (usually 1 liter). Once you calculate the volume needed, carefully dilute the liquid HCl with distilled water in a volumetric flask to reach a total volume of 1 liter. Be cautious when handling concentrated HCl as it is corrosive and can cause burns.
To calculate the number of moles of HCl, you need to use the formula: moles = Molarity (M) x Volume (L) Convert 230 cm^3 to liters: 230 cm^3 ÷ 1000 = 0.23 L Now, plug in the values: moles = 2M x 0.23 L = 0.46 moles of HCl in 230 cm^3 of 2M hydrochloric acid.
A 2M solution of hydrochloric acid would contain 2 moles of hydrochloric acid per liter of solution. To determine the amount of hydrochloric acid in a certain volume of 2M solution, you can use the formula: moles = Molarity x Volume (in liters).
30 percent of 2m = 0.6m30% of 2m= 30% * 2m= 30%/100% * 2m= 6/10m or 0.6m
2m is 200cm..
It is: 2m times 2m is equivalent to 4m^2
2m is 2000cm
they both are same as HCl is a monobasic acid.>>>Not exactly. N stands for normal and M stands for mole. Knowing that, read this article to know the difference:http://answers.yahoo.com/question/index?qid=20070625100319AALNjoW
275cm is greater than 2m
2m = 26m = 26/2m = 13