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How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many moles of atoms are present in 154 g of HCl?
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
How do you convert 65.0 g HCl to moles?
To convert grams of a substance to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of HCl (hydrochloric acid) is 36.46 g/mol. Therefore, 65.0 g of HCl is equivalent to 65.0 g / 36.46 g/mol = 1.78 moles of HCl.
What is the name for hcL AQ?
It is actually HCl(aq) Its chemical name is Hydrochloric acid
How many grams of HCl are contained in 4.25mL of a 0.405M aqueous solution of HCl?
M * V = n 0.405 M * 0.00425 ml = 0.00172125 mole of HCl The molar mass of HCl is: 1.007947 + 35.453 = 36.460947 g/mole m = mm * n So the mass in gram is: 36.460947 g/mole * 0.00172125 mole = 0.0628 gram
How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
What is he necessary amount of chlorine needed to prepare 25.00 g of hydrogen chloride by reacting hydrogen with chlorine?
H2 (g) + Cl2 (g) --> 2 HCl (g) 25.00 g HCl x 1 mol HCl x 1 mol Cl2 x 70.90 g Cl2 = 24.3 g Cl2 are needed. ................... 36.46 g HCl . 2 mol HCl .. 1 mol Cl2
How many moles of atoms are present in 154 g of HCl?
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
if 6.5g of zn reacts with 5g of hcl?
7.3 g of HCl.
How do you convert 65.0 g HCl to moles?
To convert grams of a substance to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of HCl (hydrochloric acid) is 36.46 g/mol. Therefore, 65.0 g of HCl is equivalent to 65.0 g / 36.46 g/mol = 1.78 moles of HCl.
How many molecules are present in 0.340g of HCl?
0,34 g HCl contain 5,6.10e21 molecules.
What is the name for hcL AQ?
It is actually HCl(aq) Its chemical name is Hydrochloric acid
How many grams of HCl must be dissolved in 275.0 g of water to prepare a 1.5 molal solution?
The answer is 15,039 g hydrogen chloride (HCl).
What is common name for HCl?
Hydrogen chloride is the common name for HCl
How many grams of HCl are contained in 4.25mL of a 0.405M aqueous solution of HCl?
M * V = n 0.405 M * 0.00425 ml = 0.00172125 mole of HCl The molar mass of HCl is: 1.007947 + 35.453 = 36.460947 g/mole m = mm * n So the mass in gram is: 36.460947 g/mole * 0.00172125 mole = 0.0628 gram
Find out the mass of HCL needed to react completely with 0.20 g of ammonia gass?
Use grams to moles to moles to grams: 0.2 g of ammonia gas (NH3) is equivalent to 0.012 moles of NH3 (divide by 17g/mole) One mole of NH3 reacts with one mole of HCl: NH3 + HCl <=> NH4Cl So we need 0.012 moles of HCl to react with 0.012 moles of NH3 0.012 moles HCl * 36.5 g/mole HCl => 0.43 g HCl
Why standard normality of HCl is 11.3 N?
g HCl solution = 2500 mL of HCl * 1 liter/1000 mL * 1190 g/L = 2975 g 37% solution (37 g HCl/100 grams of solution) gives you the grams of HCl: g HCl = 0.37 * 2975 g = 1100.8 g HCl Moles HCl = 1100.8/(36.46 g/mole) = 30.2 moles Therefore the molarity, which equals the normality in this case = 30.2 moles/2.5 L = 12.07 M = 12.07 N If you want to make 100 mL of a 0.1 N solution, Volume of HCl solution needed = (0.1 N * 100 mL) /12.07 N = 0.83 mL Take 0.83 mL of the 37% HCl, and dilute it with water to 100 mL.
