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How many moles are contained in 22.23 g KBr?
To find the number of moles in 22.23 g of KBr, we need to divide the given mass by the molar mass of KBr. The molar mass of KBr is 119 g/mol. Therefore, 22.23 g of KBr is equal to 0.187 moles.
How many grams does 3.30 moles of KBr weigh?
There are two steps to solving this problem:Step 1: Calculate the molar mass of KBr (molar mass is the amount, in grams, that one mole of a substance weighs).From the periodic table, we see that the molar mass of K is 39.10 g/mol (its average atomic mass). Similarly, the molar mass of Br is 79.90 g/mol. Adding these numbers together gives the molar mass of KBr, 119 g/mol.Step 2: Calculate the weight, in grams, using the molar mass and the number of moles.For every one mole of KBr, you have 119 grams of KBr:mass (m) = 119 g/mol * 3.30 molmass (m) = 392.7 gTherefore, 3.30 moles of KBr weighs approximately 392.7 grams.
How many grams of KBr are required to make 750.0 mL of solution that is 0.0552M molar mass of KBr 119.00gmol?
Multiply the molarity (M, which is in mol/L) with the volume (in L) to get the number of moles needed. Then multiply the result with the molar mass. If you look at the units they will cancel to give an answer in grams. (mol/L)*(L)=mol, (mol)*(g/mol)=g So for the numerical answer you get (0.0552 mol/L)*(0.750 L)*(119.00 g/mol)= 4.93 g KBr
What is the molar mass of potassium bromide?
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
If you have 670.0 grams of water and wish to make a 2.13 m solution of KBr how many grams of the solute would you have to add to the water that you have?
To make a 2.13 M solution of KBr, you need to determine the number of moles of KBr required using the formula Molarity = moles of solute / volume of solution in liters, then calculate the mass of KBr needed using its molar mass. Once you have the mass of KBr, you can add it to the water to prepare the solution.
How many moles are contained in 22.23 g KBr?
To find the number of moles in 22.23 g of KBr, we need to divide the given mass by the molar mass of KBr. The molar mass of KBr is 119 g/mol. Therefore, 22.23 g of KBr is equal to 0.187 moles.
How many grams does 3.30 moles of KBr weigh?
There are two steps to solving this problem:Step 1: Calculate the molar mass of KBr (molar mass is the amount, in grams, that one mole of a substance weighs).From the periodic table, we see that the molar mass of K is 39.10 g/mol (its average atomic mass). Similarly, the molar mass of Br is 79.90 g/mol. Adding these numbers together gives the molar mass of KBr, 119 g/mol.Step 2: Calculate the weight, in grams, using the molar mass and the number of moles.For every one mole of KBr, you have 119 grams of KBr:mass (m) = 119 g/mol * 3.30 molmass (m) = 392.7 gTherefore, 3.30 moles of KBr weighs approximately 392.7 grams.
A 532.1mg sample of impure kBr is treated withAgNo3 and 814.5 mg A gBr is obtaiedwhat is purity of kBr?
To find the purity of KBr, we need to calculate the percentage of KBr in the 814.5 mg of AgBr obtained. Since AgBr has a molar mass of 187.77 g/mol and KBr has a molar mass of 119 g/mol, we can find that the molar ratio of KBr to AgBr is 119/187.77. Then we can calculate the purity as (119/187.77) * (814.5/532.1) * 100%.
How many grams of KBr are required to make 750.0 mL of solution that is 0.0552M molar mass of KBr 119.00gmol?
Multiply the molarity (M, which is in mol/L) with the volume (in L) to get the number of moles needed. Then multiply the result with the molar mass. If you look at the units they will cancel to give an answer in grams. (mol/L)*(L)=mol, (mol)*(g/mol)=g So for the numerical answer you get (0.0552 mol/L)*(0.750 L)*(119.00 g/mol)= 4.93 g KBr
What is the molar mass of potassium bromide?
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
How many grams of KBr are present in 300.0 mL of a 1.25 M solution?
To find the grams of KBr in the solution, first calculate the moles of KBr present by using the molarity formula: moles = Molarity x Volume (L). Then, convert moles of KBr to grams using its molar mass. For KBr, the molar mass is approximately 119 g/mol. Finally, perform the calculation to find the grams present in the solution.
How many moles are contained in 245g of potassium bromide?
To find the number of moles in 245g of potassium bromide, first calculate the molar mass of KBr by adding the atomic masses of potassium (39.10 g/mol) and bromine (79.90 g/mol). The molar mass of KBr is 119.00 g/mol. Then, divide the given mass by the molar mass: 245g / 119.00 g/mol = 2.06 moles of potassium bromide.
If you have 670.0 grams of water and wish to make a 2.13 m solution of KBr how many grams of the solute would you have to add to the water that you have?
To make a 2.13 M solution of KBr, you need to determine the number of moles of KBr required using the formula Molarity = moles of solute / volume of solution in liters, then calculate the mass of KBr needed using its molar mass. Once you have the mass of KBr, you can add it to the water to prepare the solution.
What is the mass of bromine in 50.0g potassium bromide?
The chemical formula of potassium bromide is KBr, showing that each formula unit contains equal numbers of potassium and bromine atoms. The gram atomic masses of potassium and bromine are 39.0983 and 70.904 respectively. Therefore, the mass fraction of bromine in KBr is 70.904/(70.904 + 39.0983) or about 0.644568. 50.0 g of potassium bromide therefore contains 32.2 g of bromine, to the justified number of significant digits.
How many grams are in 3 mole of KBr?
Easy...the periodic table gives the average mole weight of each element averaged out over all it's naturally occurring, if any, isotopes, i.e., K is 39.09 Br is 79.9 Add them up and it's (to three significant figures): So KBr is 119 g/mole
What is the formula weight of KBr?
The formula weight of KBr (potassium bromide) is calculated by adding the atomic weights of potassium (K) and bromine (Br) together. The atomic weight of potassium is approximately 39.1 g/mol and bromine is approximately 79.9 g/mol. Therefore, the formula weight of KBr is approximately 39.1 + 79.9 = 119 g/mol.
How many grams of solute are present in 365 mL of 0.590 M KBr?
To find the grams of solute, first calculate the moles of KBr in 365 mL of 0.590 M solution. This is done by multiplying the volume (in liters) by the molarity. Then, use the molar mass of KBr to convert moles to grams.
