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Multiply the molarity (M, which is in mol/L) with the volume (in L) to get the number of moles needed. Then multiply the result with the molar mass. If you look at the units they will cancel to give an answer in grams.

(mol/L)*(L)=mol, (mol)*(g/mol)=g

So for the numerical answer you get (0.0552 mol/L)*(0.750 L)*(119.00 g/mol)= 4.93 g KBr

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Q: How many grams of KBr are required to make 750.0 mL of solution that is 0.0552M molar mass of KBr 119.00gmol?
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