0
How many grams of KBr are required to make 750.0 mL of solution that is 0.0552M molar mass of KBr 119.00gmol?
Wiki User
∙ 16y ago
Multiply the molarity (M, which is in mol/L) with the volume (in L) to get the number of moles needed. Then multiply the result with the molar mass. If you look at the units they will cancel to give an answer in grams.
(mol/L)*(L)=mol, (mol)*(g/mol)=g
So for the numerical answer you get (0.0552 mol/L)*(0.750 L)*(119.00 g/mol)= 4.93 g KBr
Wiki User
∙ 16y ago
To calculate the mass of KBr needed, first determine the moles of KBr required using the formula: moles = Molarity x Volume (in liters). Then, convert moles to grams using the molar mass of KBr: mass = moles x molar mass. In this case, 0.0552M x 0.750 L = 0.0414 moles of KBr needed, which is equivalent to 4.93 grams of KBr.
Add your answer:
Earn +20 pts
How many grams of sulfosalicylic acid are required to prepare 1 liter of 3 solution?
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
How much baking soda is required to make 50 ml of a saturated solution at room temperature?
Approximately 18.4 grams of baking soda is required to make 50 ml of a saturated solution at room temperature.
What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
How much KCL is required for 500mM KCL solution?
To prepare a 500mM KCl solution, you would need to dissolve 74.55 grams of KCl in enough solvent to make 1 liter of solution.
How many grams of I2 should be added to 750 g o C Cl4 to prepare a 020 m solution?
To prepare a 0.20 M solution of I2 in CCl4, you would need to calculate the moles of I2 required first. Molarity (M) = moles of solute / liters of solution. Since you know the molarity and volume of the solution, you can calculate the moles of I2 required and then convert that to grams using the molar mass of I2.
How many grams of sulfosalicylic acid are required to prepare 1 liter of 3 solution?
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
How much baking soda is required to make 50 ml of a saturated solution at room temperature?
Approximately 18.4 grams of baking soda is required to make 50 ml of a saturated solution at room temperature.
How many grams of glucose are required to produce fifty milliliters of a 0.1 mole solution?
You need 0,9 glucose.
What weight of glucose is required to prepare 2 L of a 5 percent weight to volume solution?
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
How much KCL is required for 500mM KCL solution?
To prepare a 500mM KCl solution, you would need to dissolve 74.55 grams of KCl in enough solvent to make 1 liter of solution.
How many grams of I2 should be added to 750 g o C Cl4 to prepare a 020 m solution?
To prepare a 0.20 M solution of I2 in CCl4, you would need to calculate the moles of I2 required first. Molarity (M) = moles of solute / liters of solution. Since you know the molarity and volume of the solution, you can calculate the moles of I2 required and then convert that to grams using the molar mass of I2.
How many grams of NaCl are required to prepare 4000 mL of 5 percent solution?
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
What amount of NaOH is required to prepare 1N NaOH solution and why only that amount is used?
To prepare a 1N NaOH solution, you would need to dissolve 40 grams of NaOH in water to make 1 liter of solution. This amount is used because 1N solution means 1 mole of NaOH per liter of solution, and the molar mass of NaOH is 40 g/mol, so 40 grams of NaOH is needed to have 1 mole in 1 liter of solution.
Which is none concentrated solution containing 5 grams of salt and 10 grams of water or a solution containing 18 grams of salt and 90 grams of water?
The more concentrated solution is the one containing 18 grams of salt and 90 grams of water. This is because the concentration of the solute (salt) is higher in this solution compared to the solution containing 5 grams of salt and 10 grams of water.
How many grams of KHP will be required to titrate 50 mL of 12 M NaOh solution?
To determine the grams of KHP required, you first need to calculate the number of moles of NaOH present in the 50 mL solution. Then, using the balanced chemical equation of the titration between NaOH and KHP, you can find the mole ratio. From the mole ratio and the moles of NaOH, you can calculate the moles of KHP needed and then convert that to grams of KHP.
If you have 670.0 grams of water and wish to make a 2.13 m solution of KBr how many grams of the solute would you have to add to the water that you have?
To make a 2.13 M solution of KBr, you need to determine the number of moles of KBr required using the formula Molarity = moles of solute / volume of solution in liters, then calculate the mass of KBr needed using its molar mass. Once you have the mass of KBr, you can add it to the water to prepare the solution.
How many grams of magnesium hydroxide required to make 1M of the solution?
The molar mass of magnesium hydroxide (Mg(OH)2) is 58.32 g/mol. To prepare a 1M solution, you would need 58.32 grams of magnesium hydroxide dissolved in enough water to make 1 liter of solution.
