Oxygen is in this case -2. There are three oxygens in this problem, so the total is -6. Pb's oxidation number is the same as its ionic charge, which is +2. Everything must equal zero out if you add all the numbers together.
+2(Pb)+(Sulfur's oxidation number)-6(Oxygen)= 0
-4+(4)=0
Pb=-2
S=+4
O=-2
O= -2 and there is 4 O's so that equals -8
Pb= +2
-8 + 2 = +6
therefore S= +6
+2 for Pb
+6 for S
-2 for each O
oxidation number of I is -1. oxidation number of F is +1.
Zn has oxidation number +2; S has oxidation number -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Oxidation number of Si is +4.Oxidation number of O is -2.
Carbon atoms oxidation number is +2.Hydrogen's oxidation number is +1.Oxygen's oxidation number is -2.
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Zn has oxidation number +2; S has oxidation number -2
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Oxidation number of Si is +4.Oxidation number of O is -2.
Carbon atoms oxidation number is +2.Hydrogen's oxidation number is +1.Oxygen's oxidation number is -2.
Potassium's oxidation number is +1. Chromium's oxidation number is +6. Oxygen's oxidation number is -2.
Oxidation number of Li is +1. Oxidation number of oxygen is -2.
PbSO3 is Lead (11) sulfite...In this case..if ide then it is a 3if ite then one higher which is 4if ate then one lower which is 2
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7
The Oxidation number for Kr which is krypton is 2. The Oxidation number for Kr which is krypton is 2. The Oxidation number for Kr which is krypton is 2.