The molar mass of NaOH (sodium hydroxide) is approximately 40 g/mol.
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
Standardizing the NaOH solution by dissolving a measured mass of solid NaOH ensures that the concentration of the solution is accurately known and consistent for use in experiments or analyses.
To find the number of moles in 12.0 g of NaOH, you first need to calculate its molar mass. The molar mass of NaOH (sodium hydroxide) is 39.997 g/mol. Next, you divide the given mass by the molar mass: 12.0 g / 39.997 g/mol ≈ 0.30 moles of NaOH.
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
The molar mass of NaOH is 40 g/mol. The molar mass of sodium is 23 g/mol. Therefore, the percent by mass of sodium in NaOH is (23 g/mol / 40 g/mol) x 100% = 57.5%.
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
The molarity of NaOH solution is 0.010 mol/L. To find the mass, you need to multiply the molarity by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol. Therefore, the mass of NaOH in 2.5 L of 0.010 M solution is 1 g.
To find the mass of NaOH, first calculate the number of moles in 290 mL of a 1.7 M solution using the formula: moles = concentration (M) x volume (L). Then, use the molar mass of NaOH (40 g/mol) to convert moles to grams: mass = moles x molar mass.
Standardizing the NaOH solution by dissolving a measured mass of solid NaOH ensures that the concentration of the solution is accurately known and consistent for use in experiments or analyses.
To find the number of moles in 12.0 g of NaOH, you first need to calculate its molar mass. The molar mass of NaOH (sodium hydroxide) is 39.997 g/mol. Next, you divide the given mass by the molar mass: 12.0 g / 39.997 g/mol ≈ 0.30 moles of NaOH.
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
The molar mass of NaOH is 40 g/mol. The molar mass of sodium is 23 g/mol. Therefore, the percent by mass of sodium in NaOH is (23 g/mol / 40 g/mol) x 100% = 57.5%.
To convert grams of NaOH to moles, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). Thus, 20 grams of NaOH is equivalent to 0.5 moles (20 g / 40 g/mol).
To find the number of moles of NaOH in a 36.65g sample, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is 40g/mol (sodium 22.99g/mol + oxygen 16.00g/mol + hydrogen 1.01g/mol). So, 36.65g ÷ 40g/mol = 0.9163 moles of NaOH.
This depends on the mass of NaOH dissolved in 1 L water.