The molar mass of NaOH is 40 g/mol. The molar mass of sodium is 23 g/mol. Therefore, the percent by mass of sodium in NaOH is (23 g/mol / 40 g/mol) x 100% = 57.5%.
The molar mass of NaOH (sodium hydroxide) is approximately 40 g/mol.
Sodium hydroxide (chemical composition NaOH) has an atomic mass of 40 amu which is also 40 grams/mole
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
To find the number of moles of NaOH in a 36.65g sample, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is 40g/mol (sodium 22.99g/mol + oxygen 16.00g/mol + hydrogen 1.01g/mol). So, 36.65g ÷ 40g/mol = 0.9163 moles of NaOH.
The percent composition of NaOH can be calculated by dividing the mass of each element by the molar mass of NaOH and then multiplying by 100. For NaOH, the percent composition is approximately 39% Na (sodium) and 61% O (oxygen), as there is only one atom of each in the compound.
The molar mass of NaOH (sodium hydroxide) is approximately 40 g/mol.
Sodium hydroxide (chemical composition NaOH) has an atomic mass of 40 amu which is also 40 grams/mole
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
To find the number of moles of NaOH in a 36.65g sample, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is 40g/mol (sodium 22.99g/mol + oxygen 16.00g/mol + hydrogen 1.01g/mol). So, 36.65g ÷ 40g/mol = 0.9163 moles of NaOH.
For this you need the atomic (molecular) mass of NaOH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaOH= 40.083.0 grams NaOH / (40.0 grams)= 2.08 moles NaOH
4.00% (percent) by mass (weight) means 4.00g for each 100g of solution. There are 2 x 100g of water, so 2 x 4g =8.00g of NaOH (sodium hydroxide) But, a 4% aqueous solution of NaOH should mean it's 96% (96g) water. There are 2.08333 x 96g of water, so 2.08333 x 4g = 8.33g of NaOH.
Sodium hydroxide has the formula NaOH and it contains three atoms, one each of Sodium, Hydrogen and Oxygen.
Datagiven Mass =60 gramFormula mass=40Volume=50Molality=?m =Mass of solution_________________*LitreFormula mass Volume60 * 100040 50060000_____20000m=3gram Ans
To determine the number of moles in 4g of sodium hydroxide (NaOH), divide the mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40g/mol (Na = 23g/mol, O = 16g/mol, H = 1g/mol). Therefore, 4g of NaOH is equal to 0.1 moles.
To calculate the mass of 2.5 moles of sodium hydroxide (NaOH), you need to know the molar mass of NaOH, which is 40 g/mol. Multiply the number of moles by the molar mass: 2.5 moles x 40 g/mol = 100 grams of sodium hydroxide.