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pH + pOH = 14.

So pOH = 14 - 1.12 = 12.88

pOH = -log[OH-]

[OH-] = 1.31 x 10-13 M

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11y ago
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12y ago

pH + pOH = 14

12.4 + pOH = 14

pOH = 1.6

pOH = -log[OH-]

1.6 = -log[OH-]

10-1.6 = [OH-] = 0.0251 M

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Q: How do you calculate OH- with a ph of 1.12?
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