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From the equilibrium of water dissociation,
kW is equal to the product of hydrogen ions and hydroxyl ions. The hydrogen ion concentration is 1x10^(-4). Hence, at 298 K, the hydroxyl ion concentration would be 1x10^(-10).
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What is the OH concentration of a 1 M HCL solution?
Water equilibrium equation: Kw = [H+] * [OH-] = 1.0*10-14 (at 25oC)So [OH-] = 1.0*10-14 / 1.0 M HCl = 1.0*10-14 mol/L OH-
How many moles of HCL is present in 1 liter of stomach solution that has a PH of 1?
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
Balanced equation for HCl and NaOH?
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
If it requires 40 ml of 3.5 m naoh to neutralize 55 of hcl what is the molarity of the hcl solution?
40 ml of NaOH contains 0.04 L * 3.5 M = 0.14 mole of NaOH Since NaOH donates 1 OH you will also have 0.14 mole of OH- in solution. This can be neutralised with an equal amount of H+. HCl can donate 1 H+, so you need an equal amount of H+ to neutralise the OH-. So you need 0.14 mole of the HCl. 55 ml has 0.14 mole HCl. So the molarity is: 0.14 mole / 0.055 L = 2.54 M
Calculate the pH of 0.01m hcl?
HCl is a strong acid, so we assume that it completely breaks up into ions in solution. HCl ----> H+ & Cl- if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl- pH = -log [H+] pH = -log 0.01 pH = 2
What is the OH concentration of a 1 M HCL solution?
Water equilibrium equation: Kw = [H+] * [OH-] = 1.0*10-14 (at 25oC)So [OH-] = 1.0*10-14 / 1.0 M HCl = 1.0*10-14 mol/L OH-
How many moles of HCL is present in 1 liter of stomach solution that has a PH of 1?
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
Balanced equation for HCl and NaOH?
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)
If it requires 40 ml of 3.5 m naoh to neutralize 55 of hcl what is the molarity of the hcl solution?
40 ml of NaOH contains 0.04 L * 3.5 M = 0.14 mole of NaOH Since NaOH donates 1 OH you will also have 0.14 mole of OH- in solution. This can be neutralised with an equal amount of H+. HCl can donate 1 H+, so you need an equal amount of H+ to neutralise the OH-. So you need 0.14 mole of the HCl. 55 ml has 0.14 mole HCl. So the molarity is: 0.14 mole / 0.055 L = 2.54 M
Calculate the pH of 0.01m hcl?
HCl is a strong acid, so we assume that it completely breaks up into ions in solution. HCl ----> H+ & Cl- if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl- pH = -log [H+] pH = -log 0.01 pH = 2
How much of a 2 mole NaOH solution would be required to neutralize 20mL of a 6 mole HCl solution?
I assume you mean molar instead of mole?Fast:The HCl solution is 3 times as concentrated.Since both can only donate 1 H+ or OH-...you wil need 3 times as much NaOH to neutralise the HCl.20 ml * 3 = 60 mlSlow:The HCl solution has 6 mol/LThere is 20 ml of it, so you have 0.02 L * 6 mol/L = 0.12 mol of HClEach mole of HCl donates 1 mole of H+So there is 0.12 mol of H+ that you have to neutralise.This equals to 0.12 mol OH-Each NaOH donates 1 OH-So you need 0.12 mol NaOHThe NaOH solution you are using has 2 mol/LSo you have to use 0.12 mol / 2 mol/L = 0.06 L = 60 ml
0.05N HCL means what?
For example, an 1 L solution containing 1,823047 g HCl.
How to prepare 0.2N HCl solution?
0.2 N HCl solution means 0.2 equivalents of HCl dissolved in 1 litre of water. Normality = Molarity x n-factor => Molarity =Normality/n-factor=0.2/1=0.2 M 0.2 moles should be present in 1 litre of solution. 0.2moles =0.2 x 36.5 = 7.3 grams of HCl =>Dissolve 7.3 grams of HCl in 1 litre if water to get a 0.2N solution.
How to prepare HCL solution?
Prepare HCl 1 M by HCl concentration 37 % HCl concentration 37 % have density =1.19 g/ml HCl 1 M use HCl 37 % 82.81 ml make volume with water to 1 liter
What has a pH of 1 and completely ionizes in aqueous solution?
HCl
What If enough water is added to 5 g of HCl to make 1 liter of solution what is the pH?
Find moles HCl. 5 g HCl (1 mole HCl/36.450 grams) = 0.1372 moles HCl Now, Molarity = moles of solute/Liters of solution Molarity = 0.1372 moles HCl/1 liter = 0.1372 M HCl Then. -log(0.1372 M HCl) = 0.9 pH ( you might call it 1, but pH can be off the scale ) -----------
How can you prepare several different pH solutions from a 1 Molar stock solution of HCl?
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
