Water equilibrium equation: Kw = [H+] * [OH-] = 1.0*10-14 (at 25oC)
So [OH-] = 1.0*10-14 / 1.0 M HCl = 1.0*10-14 mol/L OH-
The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).
The concentration of a solution is given by the formula: concentration = moles of solute / volume of solution in liters. However, to determine the concentration in this case, we need to know the moles of HCl in the solution. Given that the concentration is 0.5 M, it means there are 0.5 moles of HCl in every liter of solution. To find out how many moles are in 400 ml (0.4 L) of 0.5 M HCl solution, we use the formula: moles = concentration x volume. moles = 0.5 M x 0.4 L = 0.2 moles. Therefore, the concentration of 400 ml of 0.5 M HCl solution is 0.5 M.
Concentration of H+ can be written as [H+]. The square brackets denote "concentration of".Mr HCl = 36.5 g mol-1Moles HCl = 0.1 g / 36.5 g mol-1= 2.74 x 10-3 mol[HCl] = 2.74 x 10-3 mol / 2.5 L= 1.1 x 10-3 mol L-1 ( or mol dm-3)[H+] = 1.1 x 10-3 mol L-1[OH-] = (10-14) / (1.1 x 10-3) = 9.13 x 10-12 mol L-1pH = 2.96= 3.0
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
From the equilibrium of water dissociation, kW is equal to the product of hydrogen ions and hydroxyl ions. The hydrogen ion concentration is 1x10^(-4). Hence, at 298 K, the hydroxyl ion concentration would be 1x10^(-10).
The normality of a solution is a measure of the concentration of a solute in a solution. For HCl (hydrochloric acid), the normality would depend on the concentration of the HCl solution. For example, a 1 M (molar) solution of HCl would be 1 N (normal).
The concentration of a solution is given by the formula: concentration = moles of solute / volume of solution in liters. However, to determine the concentration in this case, we need to know the moles of HCl in the solution. Given that the concentration is 0.5 M, it means there are 0.5 moles of HCl in every liter of solution. To find out how many moles are in 400 ml (0.4 L) of 0.5 M HCl solution, we use the formula: moles = concentration x volume. moles = 0.5 M x 0.4 L = 0.2 moles. Therefore, the concentration of 400 ml of 0.5 M HCl solution is 0.5 M.
Concentration of H+ can be written as [H+]. The square brackets denote "concentration of".Mr HCl = 36.5 g mol-1Moles HCl = 0.1 g / 36.5 g mol-1= 2.74 x 10-3 mol[HCl] = 2.74 x 10-3 mol / 2.5 L= 1.1 x 10-3 mol L-1 ( or mol dm-3)[H+] = 1.1 x 10-3 mol L-1[OH-] = (10-14) / (1.1 x 10-3) = 9.13 x 10-12 mol L-1pH = 2.96= 3.0
In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.
From the equilibrium of water dissociation, kW is equal to the product of hydrogen ions and hydroxyl ions. The hydrogen ion concentration is 1x10^(-4). Hence, at 298 K, the hydroxyl ion concentration would be 1x10^(-10).
HCl is a strong acid. Therefore, it can be expected to fully dissociate in aqueous solution, yielding one hydrogen ion and one chloride ion per molecule. The concentration of the hydrogen ion should thus be the same as the initial concentration of the HCl. Therefore, a 0.10M HCl solution has an H+ concentration of 0.10M. By the equation pH=-log[H+], the pH of this solution is 1.
1 N HCl (hydrochloric acid) is equivalent to a concentration of 0.1 M (molarity), which means it contains 1 mole of HCl per liter of solution. The percentage of HCl in 1 N solution is about 3.65%, calculated based on the molecular weight of HCl.
The pH of a 1N HCl solution can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution. For a 1N solution of HCl, the concentration of H+ ions will be 1M, so the pH will be -log(1) = 0.
HCl is a strong acid, so we assume that it completely breaks up into ions in solution. HCl ----> H+ & Cl- if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl- pH = -log [H+] pH = -log 0.01 pH = 2
To prepare a 2M HCl solution from liquid HCl, you need to calculate the volume of the liquid HCl required. Since the concentration of the stock solution is not provided, you can use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired final concentration (2M), and V2 is the final volume of the solution (usually 1 liter). Once you calculate the volume needed, carefully dilute the liquid HCl with distilled water in a volumetric flask to reach a total volume of 1 liter. Be cautious when handling concentrated HCl as it is corrosive and can cause burns.
To prepare 1 M hydrochloric acid (HCl) solution, you usually need to dilute concentrated HCl solution (~35-37% HCl) with water in a specific ratio. The specific volume of concentrated HCl needed depends on its concentration and the final volume of the 1 M solution you want to make. In this case, 85 ml of concentrated HCl is likely to be the volume needed to make 1 L of 1 M HCl solution.
0.05N HCl refers to a hydrochloric acid solution with a concentration of 0.05 moles per liter. This solution is often used in various chemical reactions, titrations, and laboratory experiments to provide a specific acid concentration.