The number of atoms per mole of any element, or the number of molecules per mole of any compound, is 6.0223 x 1023 atoms. Therefore, by multiplication, 6.0223 x 1023 * 5 = 3.01107075 x 1024 atoms in 5 moles of Sodium (Na).
I am assuming that the question refers to ormual inits in 0.5M of sodium chloride. Obviously there are no NACL units in elemnetal sodium.
the obvious answer is 0.5 assuming that what is meant by a formula unit is the same as gram molecule.
However if you mean the number of sodium chloride "molecules"(bearing in min in 0.5m the answer is Avogadros number divide by 2 so 3.01 X 1023
Formula unit is not a very precise term.
The formula for converting moles to atoms is number of moles × Avogadro's constant
Avogadro's constant = 6.022 × 1023
0.75 mole Na × (6.022 × 1023) = 4.517 × 1023 atoms Na
The formula for converting moles to atoms is number of moles × Avogadro's constant
Avogadro's constant = 6.02 × 1023
0.5 mole Na × (6.02 × 1023) = 3.01 × 1023 atoms Na
The metals such as sodium do not have molecular formulas that contain more than one atom of the metal. Therefore, the answer is twice Avogadro's number = about 1.2044 X 1024.
One mole of sodium contains 6.02 x 1023 Na atoms. This is the avogadro constant. Thus in two moles of sodium there would be double of that, which is 1.20 x 1024.
I mole of sulfur atoms is 32 g. Thus there are 300/32 moles in 300 g, i.e. 9.375 moles.
50ml = .05L of HCL 1.0 M = 1mol / 1L of HCL simply multiply - .05 by 1.0, and get your answer!
At low concentrations, normality and molarity are about the same. So figure out how many grams are in a mole of KOH: K-39, O-16, H-1, so 39+16+1=56g/mol. 0.05 moles would be 56(.05)=2.8g, so dissolve 2.8 grams of KOH in a liter of water and you're there.
.05 cents
Releasing the Bonds was created in 2000-05.
I mole of sulfur atoms is 32 g. Thus there are 300/32 moles in 300 g, i.e. 9.375 moles.
They're around .05% sodium, according to a USDA fact sheet.
M = g/L 20 = g/0.05 20 * .05 = g 1.0 = g of solute
50 mg is .05 gm
Moles of the soild = 1.78/ 208 = .00856 moles of H2O = 0.90/ 18 =.05 therefore number of moles of water for 1 mole of solid = .05/.00856 = approx 6
50ml = .05L of HCL 1.0 M = 1mol / 1L of HCL simply multiply - .05 by 1.0, and get your answer!
137.4 g First you need to calculate the molar mass of the molecule. Be = 9.01 g/mol C = 12.01 g/mol I = 126.9 g/mol Thus BeCI2 is equivalent to ( 9.01 + 12.01 + 2(126.9) ) g/mol or 274.82 g/mol. Then, using conversions, you multiply the amount you have by the molar mass so that: (.05 mol BeCI2)*(274.82 g/mol). The moles cancel out and you are left with a weight of 137.41 g.
It will be 7805 in which 7 is company code; 8 means positive voltage & 05 is amount of positive voltage output.
generally a cap is 10 dollars. if you know a good person you can get them for 5 bucks. cap is about .05-.1g
How about this amount 1300 X .05 = 65 + 100 = 165
An iBook G3 Clamshell needs to be running Mac OS X 10.3.4 (or later) for iLife '05 to operate. Depending on the particular version of Clamshell there may be problems with the amount of hard disc space available for the iLife applications.
The date 25-05-05 in Roman numerals is XXV.V.V and the date 25-05-2005 is XXV.V.MMV