137.4 g
First you need to calculate the molar mass of the molecule.
Be = 9.01 g/mol
C = 12.01 g/mol
I = 126.9 g/mol
Thus BeCI2 is equivalent to ( 9.01 + 12.01 + 2(126.9) ) g/mol or 274.82 g/mol.
Then, using conversions, you multiply the amount you have by the molar mass so that: (.05 mol BeCI2)*(274.82 g/mol). The moles cancel out and you are left with a weight of 137.41 g.
0.05 liters (keep in mind that 1000 ml = 1 l)
The melting point of actinium is 1 050 0C.
In 1903, the U.S. penny was made of bronze, which is an alloy of copper (95%) and tin (5%). The penny continued to be made of bronze until 1982 when it was switched to a copper-plated zinc composition.
A: By saturating a transistor meaning forward bias the base to emitter the voltage across the collector and base should be very low . depending on current it can be .050 v to .5v reversing or removing the bias voltage this voltage should be the same as the rail
Well, isn't that a happy little question! 1050 milliliters is the same as 1.05 liters. Just a simple conversion, like adding a touch of color to brighten up your painting. Remember, there are 1000 milliliters in a liter, so you're just moving the decimal point over a bit. Happy painting!
The mass of 7 050 moles of natural uranium is 238,02891 x 7 050.
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
To find the mass of NaCl present in the solution, we first need to calculate the number of moles of NaCl in the solution using the formula: moles = molarity x volume. The volume here is 150 g of water, which is approximately 150 mL. Therefore, the moles of NaCl in the solution would be (0.050 mol/L) x (0.150 L) = 0.0075 moles. The molar mass of NaCl is 58.44 g/mol, so the mass of NaCl in the solution is 0.0075 moles x 58.44 g/mol = approximately 0.44 g.
Carbon as represent by the symbol C has a weight of 12.01 grams per mole. The given amount of ,60 grams thus represents .050 moles of C. One mole is 6.02x10^23 particles. So .60 grams, or .050 moles equates to some 3.1x10^22 atoms of C.
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
40 000 kg + 50 000 g = 40 050 000 g
19 050 kilograms
The balanced equation for the complete combustion of methane is CH4 + 2 O2 -> CO2 + 2 H2O. This equation shows that each mole of methane produces one mole of carbon dioxide. The mass of carbon dioxide produced by complete combustion of any mass of methane will therefore equal the mass of methane reacted multiplied by the ratio of the gram molecular masses of carbon dioxide and methane. The answer to the question therefore is about (6.80103)(44.0098)/(16.04276) or 18.6953 grams of carbon dioxide, to the justified number of significant digits.
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