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137.4 g

First you need to calculate the molar mass of the molecule.

Be = 9.01 g/mol

C = 12.01 g/mol

I = 126.9 g/mol

Thus BeCI2 is equivalent to ( 9.01 + 12.01 + 2(126.9) ) g/mol or 274.82 g/mol.

Then, using conversions, you multiply the amount you have by the molar mass so that: (.05 mol BeCI2)*(274.82 g/mol). The moles cancel out and you are left with a weight of 137.41 g.

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