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First find the molality--

convert the 72.4 grams into mols; convert the grams of water into kilograms. Divide the mols by the Kg, which gives you 6.419m.

No need to find the mol ions since it's a molecular compound.

The molar boiling point constant for water is 0.51.

Therefore:

Tb=0.51(6.419)

Tb=3.27

since this is the boiling point elevation and we're trying to discover the new boiling point, add this number to 100 (the average boiling point of water)

the final answer is 103.27o c

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Q: What is the boiling point of a solution of 72.4 grams of glycerol dissolved in 122.5 grams of water?
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