First find the molality--
convert the 72.4 grams into mols; convert the grams of water into kilograms. Divide the mols by the Kg, which gives you 6.419m.
No need to find the mol ions since it's a molecular compound.
The molar boiling point constant for water is 0.51.
Therefore:
Tb=0.51(6.419)
Tb=3.27
since this is the boiling point elevation and we're trying to discover the new boiling point, add this number to 100 (the average boiling point of water)
the final answer is 103.27o c
This is a homogeneous solution of ammonium hydroxide in water.
The molarity is 0,031.
The boiling point will be approx. 100,81 0C at 760 mm col. Hg.
Just add the two masses: 40 + 120 = 160 grams.
Start by looking up atomic masses of Na, N and O. Convert grams to kilograms.
mixture
This is a homogeneous solution of ammonium hydroxide in water.
The molarity is 0,031.
gjghm
The boiling point will be approx. 100,81 0C at 760 mm col. Hg.
The weight of the solution and thereby the weight of the solute.
35.3
5.2
Just add the two masses: 40 + 120 = 160 grams.
no
Start by looking up atomic masses of Na, N and O. Convert grams to kilograms.
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