Fe(OH)2
How is it formed? Fe2+ + (OH) 1- = Fe(OH)2
*remember to use subscripts
Remember to criss cross the charges. Fe has a charge of 2 and hydroxide (polyatomic) has a charge of -1. So your final product is Fe(OH)2 always put the OH in brackets because the 2 applies to everything in the brackets.
The chemical equation when sodium hydroxide is added to iron(II) is: Fe(OH)2 (iron(II) hydroxide) + 2NaOH (sodium hydroxide) -> Fe(OH)2 + 2NaOH.
The chemical name for Fe(OH)2 is iron(II) hydroxide.
Iron (II) hydroxide has a chemical formula Fe(OH)2. To find the percent of iron in iron (II) hydroxide, you need to calculate the molar mass of iron (Fe) and divide it by the molar mass of the compound Fe(OH)2, then multiply by 100 to get the percentage. The percent of iron in iron (II) hydroxide is approximately 69.9%.
Iron chloride and sodium hydroxide will make iron hydroxide and sodium chloride. For Iron II chloride the equation is: 2NaOH(aq) + FeCl2(aq) --> 2NaCl(aq) + Fe(OH)2(S). For Iron III chloride the equation is: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(S).
Fe(NO3)2 + 2NaOH-->Fe(OH)2 + 2NaNO3 (Assuming Fe is Fe (II))
The chemical equation when sodium hydroxide is added to iron(II) is: Fe(OH)2 (iron(II) hydroxide) + 2NaOH (sodium hydroxide) -> Fe(OH)2 + 2NaOH.
The chemical formula (not equation) is Fe(OH)2.
For the chemical equation, simply replace the name of each compound with its chemical formula: NaOH + FeCl2 --> Fe(OH)2 + NaCl
The chemical name for Fe(OH)2 is iron(II) hydroxide.
The products of the reaction between iron II sulfate and sodium hydroxide are iron II hydroxide and sodium sulfate. The balanced chemical equation for this reaction is FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4.
FeS is not a chemical equation but a chemical formula; FeS is the chemical formula of iron sulfide.
Iron (II) hydroxide has a chemical formula Fe(OH)2. To find the percent of iron in iron (II) hydroxide, you need to calculate the molar mass of iron (Fe) and divide it by the molar mass of the compound Fe(OH)2, then multiply by 100 to get the percentage. The percent of iron in iron (II) hydroxide is approximately 69.9%.
Iron chloride and sodium hydroxide will make iron hydroxide and sodium chloride. For Iron II chloride the equation is: 2NaOH(aq) + FeCl2(aq) --> 2NaCl(aq) + Fe(OH)2(S). For Iron III chloride the equation is: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(S).
Fe(NO3)2 + 2NaOH-->Fe(OH)2 + 2NaNO3 (Assuming Fe is Fe (II))
The precipitation reaction between an aqueous iron(II) ion (Fe^2+) and sodium hydroxide (NaOH) forms a green precipitate of iron(II) hydroxide (Fe(OH)2) according to the chemical equation: Fe^2+(aq) + 2OH^-(aq) → Fe(OH)2(s).
Word equation: Iron + Copper (II) sulfate → Iron (II) sulfate + Copper Chemical equation: Fe + CuSO4 → FeSO4 + Cu
After the reaction of iron with an acid a salt is formed, not a hydroxide.