......chem 130?
The balanced equation for the reaction of potassium with oxygen is: 4K + O2 -> 2K2O The coefficient of oxygen in this balanced equation is 1.
This chemica equation is:B2H6 + 3 O2 = B2O3 + 3 H2O
The balanced equation for the combustion of heptane is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O. Therefore, the coefficient for oxygen is 11.
2H2O2------------ 2 H2O + O2 thus correct coefficient is 2
To balance this chemical equation, start by balancing the sulfur atoms: add a coefficient of 2 in front of H2O to balance the sulfur atoms. Next, balance the hydrogen atoms by adding a coefficient of 2 in front of H2S. Finally, balance the oxygen atoms: add a coefficient of 3 in front of O2 to balance the oxygen atoms on both sides. The balanced equation is 2H2S + 3O2 → 2H2O + 2SO2.
The balanced equation for the reaction of potassium with oxygen is: 4K + O2 -> 2K2O The coefficient of oxygen in this balanced equation is 1.
To balance the combustion equation for pentanediol (C5H12O2), you start with the unbalanced equation: C5H12O2 + O2 → CO2 + H2O. After balancing the carbon, hydrogen, and oxygen atoms, the balanced equation is: C5H12O2 + 6 O2 → 5 CO2 + 6 H2O. Therefore, the coefficient of O2 in the balanced equation is 6.
To balance the equation ( C_5H_8 + O_2 \rightarrow 5CO_2 + 4H_2O ), you need to determine the appropriate coefficient for ( O_2 ). The balanced equation shows that 5 carbon atoms produce 5 ( CO_2 ) and 8 hydrogen atoms produce 4 ( H_2O ), which collectively require 9 oxygen atoms (from 5 ( CO_2 ) and 4 ( H_2O )). Therefore, the coefficient in front of ( O_2 ) is 9/2 or 4.5. To avoid fractions, you can multiply the entire equation by 2, resulting in the coefficient of 9 for ( O_2 ).
This chemica equation is:B2H6 + 3 O2 = B2O3 + 3 H2O
The balanced equation is: C5H12 + 8O2 → 5CO2 + 6H2O. Therefore, the coefficient for oxygen in the balanced equation is 8.
Since the ratio of potassium to oxygen is 2:1 in the compound, the coefficient of oxygen in the balanced equation would be 1. The balanced equation for the reaction of potassium with oxygen to form this oxide would be 4K + O2 -> 2K2O.
what is the chemical equation of nitrogen + oxygen= nitric oxide
The balanced equation for the combustion of heptane is: C7H16 + 11 O2 -> 7 CO2 + 8 H2O. Therefore, the coefficient for oxygen is 11.
The balanced equation for the complete combustion reaction is 2 C3H7OH + 9 O2 -> 6 CO2 + 4 H2O; therefore, the coefficient for oxygen is 9. If fractional coefficients are allowed, the equation can be written with only one mole of C3H7OH; in that instance the coefficient for oxygen would be 9/2.
2H2O2------------ 2 H2O + O2 thus correct coefficient is 2
To balance this chemical equation, start by balancing the sulfur atoms: add a coefficient of 2 in front of H2O to balance the sulfur atoms. Next, balance the hydrogen atoms by adding a coefficient of 2 in front of H2S. Finally, balance the oxygen atoms: add a coefficient of 3 in front of O2 to balance the oxygen atoms on both sides. The balanced equation is 2H2S + 3O2 → 2H2O + 2SO2.
To balance the chemical equation C6H12O6 + O2 → CO2 + H2O: Start by balancing the carbon atoms by placing a coefficient of 6 in front of CO2. Balance the hydrogen atoms next by placing a coefficient of 6 in front of the H2O. Lastly, balance the oxygen atoms by placing a coefficient of 6 in front of O2 on the left side of the equation. The balanced equation is: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O