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What else can I help you with?
The most common base is?
NaOH,MgOH,etc
What is the common name of the compound NaoH?
Sodium Hydroxide, otherwise known as "lye".
Why do we standardize the NaOH solution that we made by dissolving a measured mass of solid NaOH?
Standardizing the NaOH solution by dissolving a measured mass of solid NaOH ensures that the concentration of the solution is accurately known and consistent for use in experiments or analyses.
What volume of NaOH was used in the titration?
To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.
What is the concentratuon of a hcl solution if 25.0 ml is required to neutralize 38.5 ml of a 0.500m solution of naoh?
To find the concentration of HCl, you can use the formula: moles of NaOH = moles of HCl. From the given information, you can calculate the moles of NaOH used to neutralize the acid. Then, use the volume and concentration of NaOH to determine the concentration of HCl.
The most common base is?
NaOH,MgOH,etc
What is the common name of the compound NaoH?
Sodium Hydroxide, otherwise known as "lye".
How much NaOH do you use to lower pH?
You dont - adding NaOH increases pH.
How many liters of naoh are in 1.3 moles of 3.42 m of naoh?
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
Why do we standardize the NaOH solution that we made by dissolving a measured mass of solid NaOH?
Standardizing the NaOH solution by dissolving a measured mass of solid NaOH ensures that the concentration of the solution is accurately known and consistent for use in experiments or analyses.
What volume of NaOH was used in the titration?
To determine the volume of NaOH used in the titration, you need to know the concentration of the NaOH solution and the volume required to reach the endpoint. Use the formula: volume NaOH (L) = volume HCl (L) * concentration HCl / concentration NaOH.
What is the concentratuon of a hcl solution if 25.0 ml is required to neutralize 38.5 ml of a 0.500m solution of naoh?
To find the concentration of HCl, you can use the formula: moles of NaOH = moles of HCl. From the given information, you can calculate the moles of NaOH used to neutralize the acid. Then, use the volume and concentration of NaOH to determine the concentration of HCl.
How do you prepare 30 percent of NaOH?
To prepare a 30% NaOH solution, you would mix 30 grams of NaOH with enough water to make 100 grams of final solution. Be sure to use caution when handling NaOH as it is a caustic substance and can cause skin and eye irritation.
HOW TO 0.1N NaOH solution preparation?
To prepare a 0.1N NaOH solution, dissolve 4g of sodium hydroxide (NaOH) pellets in enough water to make 1 liter of solution. Use a volumetric flask to accurately measure the final volume. Remember to handle NaOH with caution as it is a caustic substance.
Why do you use ethanolic NaOH instead of aq NaOH in titration?
Ethanolic NaOH is used instead of aqueous NaOH in titration to avoid side reactions with water and reduce error in the titration process. The absence of water in ethanolic NaOH helps maintain the concentration and stability of the solution, resulting in more accurate and precise titration results.
How Many milliliters of 0.258 M NaOH are required to complétely neutrilize 2.00 g of aceitic acid HC2H3O2?
To find the volume of 0.258 M NaOH needed to neutralize 2.00 g of acetic acid (HC2H3O2), you can use the molar ratio between NaOH and acetic acid. First, determine the moles of acetic acid using its molar mass. Then, use the mole ratio from the balanced chemical equation to find moles of NaOH required. Finally, use the concentration of NaOH to find the volume needed.
How many moles of NaOH are present in 20ml of 0.5M NaOH?
To calculate the number of moles of NaOH, we use the formula: moles = molarity x volume (in liters). First, convert 20 mL to liters (0.02 L). Then, use the formula to find: moles = 0.5 mol/L x 0.02 L = 0.01 moles of NaOH present in 20 ml of 0.5M NaOH.
