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What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
What is the freezing point of a solution containing 2.50g of benzene in 120g of chloroform?
Since benzene is the solute and chloroform is the solvent, this is a non-electrolyte solution. The freezing point depression equation is ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant for chloroform, and m is the molality of the solution. From this, you can calculate the freezing point of the solution.
What is the molality of ethanol in a solution made by dissolving 14.6 g in 53.6 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. First, calculate the moles of ethanol using its molar mass and mass given, then convert the mass of water to kg. Finally, use the formula molality = moles of solute / kg of solvent to find the molality.
What is the molality of a solution made by dissolving two moles of NaOH in 6 kg of water?
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
What is the molality of a solution made by a dissolving 2 moles of naoh in 6 kg of water?
0.33 mol/kg (apex)
What is the freezing point of a solution containing 2.50g of benzene in 120g of chloroform?
Since benzene is the solute and chloroform is the solvent, this is a non-electrolyte solution. The freezing point depression equation is ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant for chloroform, and m is the molality of the solution. From this, you can calculate the freezing point of the solution.
What is the molality of ethanol in a solution made by dissolving 14.6 g in 53.6 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. First, calculate the moles of ethanol using its molar mass and mass given, then convert the mass of water to kg. Finally, use the formula molality = moles of solute / kg of solvent to find the molality.
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution made by dissolving two moles of NaOH in 6 kg of water?
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg?
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
What is the molality of a solution by dissolving 2 moles of NaOH in 10kg of water?
10kg of water contains 10l of water. So morality is 0.2mildm-3.
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
0.2
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
What is the molality of a solution made by dissolving 2 moles of NaOH in 10Kg of water?
Molality =moles of solute/kilograms of solvent Moles of solute =2
