Curium-242 has 146 neutrons and curium-244 has 148 neutrons. Also the half lives are different.
Hello, I work at The Lawrence Livermore National Laboratory and work on actinide materials, such as curium. While there are some web pages that quote it as $160/milligram, I have a hard time believing this, at least for the metal. Given the amount of time it takes to create the element, handling costs as a radioactive material, and storage issues, I would put it much higher. In short, it makes diamond, platinum, and gold equivalent to dirt!
The first nuclear reactions used to obtain berkelium-249 were:Pu-239(4n, gamma)Pu-243--------beta-------Am-243(n, gamma)Am-244-----beta-----Cm-244(5n, gamma)Cm-249--------beta----------Bk-249
The equation for the alpha decay of plutonium-244 is: [ ^{244}{94}Pu \rightarrow ^{240}{92}U + ^4_2He ]
Plutonium-244 has 94 protons (atomic number) and 150 neutrons. It is a radioactive isotope with a half-life of about 80 million years.
it is the element Californium. it is a synthetic element produced in trace quantities by helium isotope bombardment of curium. All isotopes are radioactive, chiefly by emission of alpha particles. Atomic number 98; mass numbers 244 to 254; half-lives varying from 25 minutes to 800 years.
Possible uses for thermoelectric generators (Cm 242 and Cm 244); now these isotopes has some disadvantages.
The isotope curium 244 is obtained by nuclear reactions between plutonium and neutrons. The decay of Cm 244 is by alpha disintegration, not beta.
Possible uses for thermoelectric generators (Cm 242 and Cm 244); now these isotopes has some disadvantages.Also, the scientific importance for humans knowledge.
The specific activities for some curium isotopes are:- Cm-242: 3,3.10+3 Ci/g- Cm-243: 4,2 Ci/g- Cm-244: 82 Ci/g- Cm-245: 0,1 Ci/g- Cm-246: 0,36 Ci/g
Anything from 235 to 244
6 + (23 424 243 423 423 243 244 224 242 424) = 23 424 243 423 423 243 244 224 242 430
four
four
The following equations will give you the number 242: 121 x 2 484/2 240 + 2 244 - 2
235, 236, 237, 238, 239, 241, 242, 243, 244
Depending on the energy of the alpha, fusion into Californium-246 could happen, or elastic Rutherford scattering could happen. If the alpha was energized enough to compensate for the reactions net mass increase (mCf - mCm - mα = 6.86MeV) and the Coulomb barrier (about 26MeV), so about 33MeV total, it could fuse into Cf246. Otherwise it'll bounce off the Cm242 via elastic scattering.
24.4 = 244/10 = 122/5 (fraction) = 242/5 (mixed number).