E = hc/(wavelength)
(Sorry but there ain't no button for lambda on the keyboard)
h = 6.63 x 10-34, c = 3 x 108
E = (6.63 x 10-34 x 3 x 108) / 495 x 10-9
E = 4.0181818... x 10-19
NB if the wavelength is in nanometers, expect the final order of magnitude to be 10-19 or thereabout.
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
The wavelength is 610 nm.
The longest wavelength that can dissociate a molecule of HI is determined by the ionization energy of the molecule. For HI, which has an ionization energy of 10.09 eV, the corresponding longest wavelength would be about 123 nm.
The energy of a photon can be calculated using the formula E=hc/λ, where h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Converting 663 nm to meters (1 nm = 1 x 10^-9 m), we get λ = 663 x 10^-9 m. Plugging in the values, we find the energy of the photon to be approximately 3.00 x 10^-19 Joules.
The formula for frequency is f = c/lambda, where c is the speed of light in a vacuum, lambda is the wavelength in meters, and f is frequency in cycles per second. So, if the wavelength is 700.5 nm, the frequency is 4.28 E14 hertz.
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
The energy of a photon with a wavelength of 500 nm is approximately 2.48 keV.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
610 nm
The energy of this photon is 3,7351.10e-19 joules.
The energy of the electron decreased as it moved to a lower energy state, emitting a photon with a wavelength of 550 nm. This decrease in energy corresponds to the difference in energy levels between the initial and final states of the electron transition. The energy of the photon is inversely proportional to its wavelength, so a longer wavelength photon corresponds to lower energy.
4.9695 nm
To determine the energy of a photon of orange light with a wavelength of 600 nm, we can use the formula E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength in meters. Converting the wavelength to meters (600 nm = 600 x 10^-9 m), we can plug the values into the formula to find the energy of the photon. The energy of a photon of orange light with a wavelength of 600 nm is approximately 3.31 x 10^-19 joules.
The wavelength can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging the given energy value into the equation and solving for λ gives a wavelength of approximately 608 nm.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, the energy of a photon with a wavelength of 518 nm is approximately 3.82 eV.