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E = hc/(wavelength)

(Sorry but there ain't no button for lambda on the keyboard)

h = 6.63 x 10-34, c = 3 x 108

E = (6.63 x 10-34 x 3 x 108) / 495 x 10-9

E = 4.0181818... x 10-19

NB if the wavelength is in nanometers, expect the final order of magnitude to be 10-19 or thereabout.

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Q: What is the energy in J of a photon with a wavelength of 495 nm?
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