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The formula weight of aluminum hydroxide Al(OH)3 is calculated by summing the atomic weights of all the elements in the compound. Aluminum has an atomic weight of approximately 26.98 g/mol, and each hydroxide group (OH) has a total molecular weight of about 17.01 g/mol. Therefore, the formula weight of Al(OH)3 is approximately 78.05 g/mol.

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What is the name of AlOH3?

Aluminum Hydroxide


Molar mass of AlOH3?

The molar mass of AlOH3 is calculated by adding the atomic masses of each element in its chemical formula. Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Therefore, the molar mass of AlOH3 is 78.02 g/mol.


What is aloh3?

Aluminum hydroxide (Al(OH)3) is a chemical compound commonly used as an antacid in medications to help reduce stomach acidity. It also has applications in water treatment and as a flame retardant in industrial processes.


How do you know Aloh3 is a base?

AlOH3 is considered a base because it can accept a proton (H+ ion) in a chemical reaction, forming Al(OH)4-. Bases are substances that can donate electron pairs to form bonds with hydrogen ions, which distinguishes them from acids.


Is AlOH3 a base acid or salt?

AcidActually, Al2O3 (s) is amphoteric, which means, depending on the environment, it can act as both a base and acid. We are able to illustrate this with these two reactions:(I) - Solving Al2O3 (s) in an acid (HCl):Al2O3 (s) + 6 HCl (aq) → 2 [AlCl3] (s, aq*) + 3 H2O (l)In this reaction, Al2O3 acts as a base-------------------------------------------------------------------(II) - Solving Al2O3 (s) in a base (NaOH):Al2O3 (s) + 3 NaOH (aq) ---> 2 Al(OH)3 (s) + 3 Na+Al(OH)3 (s) then reacts with NaOH to form NaAlO2:Al(OH)3 (s) + NaOH (aq) ---> NaAlO2 (s) + 2 H2O (l)Thus, we often write:Al2O3 (s) + 2 NaOH (aq) → 2 [NaAlO2] (s) + H2O (l)In this reaction, Al2O3 (s) acts as an acid-------------------------------------------------------------------*depending on amount of solvent used. Excessive amounts of solvent will solve the formed AlCl3 (s) into 2([Al3+][Cl-]3) (aq

Related Questions

What is the name of AlOH3?

Aluminum Hydroxide


What is the chemical formula for alminum hydroxide?

Aluminum forms a +3 ion, and hydroxide's formula is OH-, so the formula for aluminum hydroxide would be: Al(OH)3


What is the chemical compound AlOH3?

Aluminium hydroxide - Al(OH)3


Molar mass of AlOH3?

The molar mass of AlOH3 is calculated by adding the atomic masses of each element in its chemical formula. Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Therefore, the molar mass of AlOH3 is 78.02 g/mol.


Why are parentheses used to write the formula for AlOH3?

Parentheses are used for the formula Al(OH)3 to indicate that the hydroxide group (OH) is grouped together and that there are three of them bonded to the aluminum atom. This notation helps to clarify the composition and structure of the compound.


How do you Convert 42 grams AlOH3 to moles AlOH3?

That is aluminum hydroxide and as a polyatomic ion hydroxide needs to be in parenthesis. Thus; Al(OH)3 This shows aluminum's 3+ oxidation state and the three matching hydroxides 1- state. 42 grams Al(OH)3 ( 1 mole Al(OH)3/78.004 grams) = 0.538 moles Al(OH)3 As significant figures require; 0.54 moles Al(OH)3


What is aloh3?

Aluminum hydroxide (Al(OH)3) is a chemical compound commonly used as an antacid in medications to help reduce stomach acidity. It also has applications in water treatment and as a flame retardant in industrial processes.


Is AlOH3 an acid or a base?

Al(OH)3 is a base (Aluminum hyroxide)


What is the compound OH3?

The chemical compound OH3 does NOT exist. Water is OH2, and there is some OH3+ in any sample of water, this is due to the dissocation of water.


How much of this compound alcl3 you are going to obtain if you have a reaction of 385 g aloh3 with 256 g hcl you also must indicate the limiting reactant balance aloh3 3 hcl - alcl3 3 h2o?

The reaction equation with conventional capitalization is: Al(OH)3 + 3 HCl -> AlCl3 + 3 H2O. The gram formula unit masses are 78.00 for aluminum hydroxide, 133.34 for aluminum chloride, 36.46 for hydrogen chloride, and 18.015 for water. Therefore, the relative mass ratios are (78.00) to [3(18.015)] or about 1.443 for the ratio of the two reactants. The mass ratio of the specified available amounts of the two reactants is 385/256 or about 1.503, which is greater than the theoretical amount. Therefore, the limiting reactant is HCl. The stoichiometric reactant mass ratio of aluminum chloride to hydrogen chloride is about 133.34/(3)(36.46) or about 1.219. Therefore, a fully reacted amount of 256 g of hydrogen chloride will produce about (1.219)(256) or about 312 g of aluminum chloride. (The provided data for masses has three significant digits, so that the answer should also have three significant digits.)


Is AlOH3 a base nuluiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii...?

Al(OH)3


What are the products of AlOH3 plus 3 H2O?

When Na2CO3 reacts with Nitric acid, The products at first are Sodium Hydrogen Carbonate and Sodium Nitrate... HNO3 + Na2CO3 --> NaNO3 + NaHCO3 If again The leftover Sodium hydrogen carbonate is made to react with Nitric Acid, then the products will be: HNO3 + NaHCO3 --> NaNo3 + H2O + CO2