24.305 grams/mole Magnesium X 5 moles = 121.525 grams.
The correct number of significant digits depends on the values given in the question. Since there was only one value (5), and it refers to a perfect integer amount (5 moles). The question of the correct number of significant digits is undefined and depends entirely on the number of significant digits available for the Atomic Mass of Magnesium. Since there are 5 significant digits in the Atomic mass used, the answer would be correctly stated as 121.53 grams to 5 significant digits.
The mass of 5.90moles of magnesium chloride MgCl2 is 561,75 g (for the anhydrous salt).
5,00 g of magnesium represent 0,206 moles.
100(0.325/0.421) or 77.2 %, to the justified number of significant digits.
The percentage of silver nitrate by weight is 100[5.48/(5.48 + 25.0)] = 18.0 %, to the justified number of significant digits.
The gram atomic mass of titanium is 47.867. Therefore, in a 0.65 mole sample, there will be 0.65 X 47.867) = 31 grams, to the justified number of significant digits.
The gram molecular mass of carbon dioxide is 44.01. Therefore, 418 grams contains 418/44.01 or 9.50 moles, to the justified number of significant digits.
To find empirical formulas, masses of elemental reactants must be changed to gram atoms by dividing the mass by the gram atomic masses of each element. Thus, 16 grams of sulfur constitutes 16/32.06 or 0.50 mole to the justified number of significant digits, and 24 grams of oxygen constitutes 24/15.9994 or 1.50 moles of oxygen to the justified number of significant digits. Therefore, the atomic ratio of oxygen to sulfur in the compound is 1.50/0.50 or 3, and the empirical formula is SO3.
It is 13.2 grams.
There are 4 significant digits
The gram atomic mass of germanium is 72.6, to two significant digits. Therefore, in a 3.11 mole sample there will be (3.11)(72.6) = 226 grams, to the justified number of significant digits.
100(0.325/0.421) or 77.2 %, to the justified number of significant digits.
20.009 has five significant digits. The g isn't a digit and probably stands for grams.
The 3 and the 2.
All four of them.
For an element such as lithium, the technically correct term is "gram atomic mass" instead of "mole", and for lithium, the gram atomic mass is about 6.941. Therefore, the answer to the question is (5.48)(6.941) or 37.5 grams, to the justified number of significant digits.
The formula of sodium chloride is NaCl; therefore, the gram formula mass of sodium chloride is the sum of the gram atomic masses of sodium and chloride, or 58.443, to the justified number of significant digits. The number of gram formula masses in 23.376 grams is therefore 23.376/58.443 or 0.399998, to the justified number of significant digits.
Assuming that the "oz" means avoirdupois weight ounces,1.75 oz X 28.5 grams/ounce = 49.9 grams, to the justified number of significant digits.
1.6700 * 104 grams or 1.67*104 grams if the trailing 0s are not significant digits.
There are four significant figures in 33050. The trailing zero is not significant because there is no decimal. There would be five significant figures in 33050. If we were to remove the last zero in the number, we would alter the value of the number. Had the number been 3305.0, then there would have been four significant digits.