24.305 grams/mole Magnesium X 5 moles = 121.525 grams.
The correct number of significant digits depends on the values given in the question. Since there was only one value (5), and it refers to a perfect integer amount (5 moles). The question of the correct number of significant digits is undefined and depends entirely on the number of significant digits available for the Atomic Mass of Magnesium. Since there are 5 significant digits in the Atomic mass used, the answer would be correctly stated as 121.53 grams to 5 significant digits.
100(0.325/0.421) or 77.2 %, to the justified number of significant digits.
The gram molecular mass of carbon tetrachloride is 12.011 + 4(35.453) or 153.823. Each mole contains Avogadro's Number of molecules. Therefore, the number of molecules in 200 grams is (200/153.823) X Avogadro's Number or 7.83 X 1023 molecules, to the justified number of significant digits.
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023..06 grams C / (12.0 grams) × (6.02 × 1023 atoms) = 3.01 × 1021 atoms
The percentage concentration of the solution can be calculated as (mass of solute / total mass of solution) x 100. In this case, the mass of the solute (AgNO3) is 5.48 grams and the total mass of the solution is 5.48 grams (AgNO3) + 25.0 grams (water) = 30.48 grams. Therefore, the percentage concentration is (5.48 / 30.48) x 100 ≈ 17.98%.
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
It is 13.2 grams.
There are 4 significant digits
The gram atomic mass of germanium is 72.6, to two significant digits. Therefore, in a 3.11 mole sample there will be (3.11)(72.6) = 226 grams, to the justified number of significant digits.
20.009 has five significant digits. The g isn't a digit and probably stands for grams.
The 3 and the 2.
All four of them.
The formula of sodium chloride is NaCl; therefore, the gram formula mass of sodium chloride is the sum of the gram atomic masses of sodium and chloride, or 58.443, to the justified number of significant digits. The number of gram formula masses in 23.376 grams is therefore 23.376/58.443 or 0.399998, to the justified number of significant digits.
Assuming that the "oz" means avoirdupois weight ounces,1.75 oz X 28.5 grams/ounce = 49.9 grams, to the justified number of significant digits.
1.6700 * 104 grams or 1.67*104 grams if the trailing 0s are not significant digits.
There are four significant figures in 33050. The trailing zero is not significant because there is no decimal. There would be five significant figures in 33050. If we were to remove the last zero in the number, we would alter the value of the number. Had the number been 3305.0, then there would have been four significant digits.
Simply cut off the extra digits: 3.
Assuming that the questioner meant 60.9 cubiccentimeters, the answer is 56/60.9 = 0.92 grams per cubic centimeter. Only two significant digits are justified since this is the number of significant digits in 56 g as stated.