molar mass SO3 = 80 g/mole. 1.12 moles x 80 g/mole = 89.6 grams
The mass in grams of 1.12 moles of SO3 is 89,674 g.
The molar mass of sulfur dioxide is 64,066 g.
2S + 3O2 >> 2SO3 8.0 grams O2 (1 mole O2/32 grams)(2 mole SO3/3 mole O2) = 0.1666 ( 0.17 moles SO3 ) and also, 0.1666 moles SO3 (80.07 grams/1 mole SO3) = 13.34 ( 13 grams SO3 ) if needed.
Balanced equation. 2S + 3O2 --> 2SO3 1.32 moles O2 (2 moles SO3/3 moles O2) = 0.880 moles sulfur trioxide produced ========================
Molar mass of (NH4)2SO4 is 132.14 g/mol, so4.69 (g) / 132.14 (g/mol) = 0.0355 mol
Since oxygen is diatomic it requires 2 moles of oxygen.
The molar mass of sulfur dioxide is 64,066 g.
2S + 3O2 >> 2SO3 8.0 grams O2 (1 mole O2/32 grams)(2 mole SO3/3 mole O2) = 0.1666 ( 0.17 moles SO3 ) and also, 0.1666 moles SO3 (80.07 grams/1 mole SO3) = 13.34 ( 13 grams SO3 ) if needed.
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
Balanced equation. 2S + 3O2 --> 2SO3 1.32 moles O2 (2 moles SO3/3 moles O2) = 0.880 moles sulfur trioxide produced ========================
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
convert to mol, (divide by molar mass) then multiply by 22.4
Molar mass of (NH4)2SO4 is 132.14 g/mol, so4.69 (g) / 132.14 (g/mol) = 0.0355 mol
1 mole of sulfuric acid=98g(?)chemical formula of sulfuric acid=H2SO4Atomic mass of Hydrogen(H)=1Atomic mass of Sulpher(S)=32Atomic mass of Oxygen(O)=16(1)2+32+(16)4=2+32+64=98uTo calculate number of molesNo. of moles=given mass/atomic massno. of moles=49/98no. of moles is 0.5g
the percent sulfur by mass in so3 is 40.050%
Since oxygen is diatomic it requires 2 moles of oxygen.
2.24 L O2 (= 0.100 mol O2) is needed to react with 0.200 moles of SO2 to form SO3
1.88 X 1024 molecules SO3 (1 mole SO3/6.022 X 1023)(80.07 grams/1 mole SO3) = 250 grams sulfur trioxide ===================