convert to mol, (divide by molar mass) then multiply by 22.4
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
The molar mass of sulfur trioxide (SO3) is approximately 80.06 grams per mole.
To determine the maximum amount of SO3 that can be produced, we need to find the limiting reactant first. Given 1.0g of S and 1.0g of O2, we calculate the number of moles for each reactant. Then, we find the mole ratio from the unbalanced equation and determine which reactant is limiting. Finally, we can calculate the maximum amount of SO3 that can be produced from the limiting reactant.
Al2(SO3)3 = aluminum sulfite
We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula
To calculate the grams of sulphur trioxide, first find the molar mass of SO3 (80.06 g/mol). Next, calculate the number of moles in 1.88 x 10^24 molecules. Then, multiply the number of moles by the molar mass to get the grams.
About 245 grams.
If 32 liters of SO2 react completely, they will produce an equal volume of SO3, because the reaction is balanced. Therefore, the total number of liters of SO3 produced will also be 32 liters.
About 245 grams.
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
To find the mass of 1.12 moles of SO3, you first need to determine the molar mass of SO3. Sulfur has a molar mass of approximately 32.06 g/mol, and each oxygen atom has a molar mass of approximately 16.00 g/mol. Adding these together gives a molar mass of SO3 as approximately 80.06 g/mol. Multiplying the molar mass by the number of moles gives the mass of 1.12 moles of SO3 as approximately 89.67 grams.
2S + 3O2 >> 2SO3 8.0 grams O2 (1 mole O2/32 grams)(2 mole SO3/3 mole O2) = 0.1666 ( 0.17 moles SO3 ) and also, 0.1666 moles SO3 (80.07 grams/1 mole SO3) = 13.34 ( 13 grams SO3 ) if needed.
3 and SO3 is an anion with a +1 charge
The are two elements in SO3: sulfur and oxygen.
Formula: SO3
The molar mass of sulfur trioxide (SO3) is approximately 80.06 grams per mole.
SO3 is the chemical formula for sulfur trioxide.