To find the mass of 1.12 moles of SO3, you first need to determine the molar mass of SO3. Sulfur has a molar mass of approximately 32.06 g/mol, and each oxygen atom has a molar mass of approximately 16.00 g/mol. Adding these together gives a molar mass of SO3 as approximately 80.06 g/mol. Multiplying the molar mass by the number of moles gives the mass of 1.12 moles of SO3 as approximately 89.67 grams.
To calculate the grams of sulphur trioxide, first find the molar mass of SO3 (80.06 g/mol). Next, calculate the number of moles in 1.88 x 10^24 molecules. Then, multiply the number of moles by the molar mass to get the grams.
To find the number of moles, you first need to calculate the molar mass of SO3, which is 80.06 g/mol. Then, you can use the formula: moles = mass / molar mass. Thus, for 20g of SO3, you would have 20g / 80.06 g/mol = 0.25 moles of SO3.
2S + 3O2 >> 2SO3 8.0 grams O2 (1 mole O2/32 grams)(2 mole SO3/3 mole O2) = 0.1666 ( 0.17 moles SO3 ) and also, 0.1666 moles SO3 (80.07 grams/1 mole SO3) = 13.34 ( 13 grams SO3 ) if needed.
To calculate the mass of 3.65 x 10^20 molecules of SO3, first calculate the molar mass of SO3 (80.06 g/mol). Next, convert the number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol). Finally, use the molar mass to convert moles to grams. Mass of 3.65 x 10^20 molecules of SO3 = (3.65 x 10^20 molecules / 6.022 x 10^23 molecules/mol) * 80.06 g/mol ≈ 0.49 g.
The balanced chemical equation for the reaction is 2SO2 + O2 -> 2SO3. This means that for every 1 mole of O2 consumed, 2 moles of SO3 are produced. Therefore, 1.32 moles of O2 would produce 2.64 moles of SO3.
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
To find the number of moles, you first need to calculate the molar mass of SO3, which is 80.06 g/mol. Then, you can use the formula: moles = mass / molar mass. Thus, for 20g of SO3, you would have 20g / 80.06 g/mol = 0.25 moles of SO3.
To calculate the grams of sulphur trioxide, first find the molar mass of SO3 (80.06 g/mol). Next, calculate the number of moles in 1.88 x 10^24 molecules. Then, multiply the number of moles by the molar mass to get the grams.
2S + 3O2 >> 2SO3 8.0 grams O2 (1 mole O2/32 grams)(2 mole SO3/3 mole O2) = 0.1666 ( 0.17 moles SO3 ) and also, 0.1666 moles SO3 (80.07 grams/1 mole SO3) = 13.34 ( 13 grams SO3 ) if needed.
To calculate the mass of 3.65 x 10^20 molecules of SO3, first calculate the molar mass of SO3 (80.06 g/mol). Next, convert the number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol). Finally, use the molar mass to convert moles to grams. Mass of 3.65 x 10^20 molecules of SO3 = (3.65 x 10^20 molecules / 6.022 x 10^23 molecules/mol) * 80.06 g/mol ≈ 0.49 g.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
The molar mass of sulfur trioxide (SO3) is approximately 80.06 grams per mole.
The balanced chemical equation for the reaction is 2SO2 + O2 -> 2SO3. This means that for every 1 mole of O2 consumed, 2 moles of SO3 are produced. Therefore, 1.32 moles of O2 would produce 2.64 moles of SO3.
1 mole of sulfuric acid=98g(?)chemical formula of sulfuric acid=H2SO4Atomic mass of Hydrogen(H)=1Atomic mass of Sulpher(S)=32Atomic mass of Oxygen(O)=16(1)2+32+(16)4=2+32+64=98uTo calculate number of molesNo. of moles=given mass/atomic massno. of moles=49/98no. of moles is 0.5g
The most straightforward reaction for the formation of SO3 from SO2 is 2 SO2 + O2 => 2 SO3. If this is the actual reaction for the formation, 3 moles of SO3 are formed from 3 moles of SO2.
To find the number of moles in 4.69 g of (NH4)2SO4, you need to first calculate the molar mass of (NH4)2SO4. The molar mass of (NH4)2SO4 is 132.14 g/mol. Then, you can use the formula: moles = mass / molar mass. Therefore, moles = 4.69 g / 132.14 g/mol ≈ 0.035 moles of (NH4)2SO4.
To convert grams to liters for a gas like SO3, you would need to know the temperature, pressure, and molar mass of the gas. Without this information, it is not possible to determine the volume in liters.