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One look at a Periodic Table tells you the molar mass of sodium (Na) is 22.99 g/mol.
So multiply your mol value by the g/mol value to get a value in grams!
2.0x10-3 x 22.99 = !!!
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∙ 13y ago
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∙ 15y agoFor this you need the atomic (molecular) mass of N2. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel. N2= 28.0 grams
2.23 moles N2 × (28.0 grams)= 62.44 grams N2
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∙ 14y agoNitrogen has 14.01 grams per mole. Therefore, 2 mole N has 2 * 14.01, or 28.02, grams.
Wiki User
∙ 13y ago67.2 grams.
One mole of N2 is equal to 28 grams (you get the atomic mass of Nitrogen, which is 14, and multiply it by two).
You then multiply 28 by 2.4 to get your answer.
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∙ 11y ago1 mole N = 14.0067g N
2.00mol N x 14.0067g N/1mol N = 28.0g N
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∙ 13y ago28 g.
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How many moles of NH3 can be produced from 14 grams of N2?
The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
How many grams of NH3 can be produced from 4.46 mol of N2 and excess H2.?
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
How many grams of NO are produced from the reaction of 2 mol of N2 with 2 mol of O2?
You have :N2 + O2 -----> 2NOmoles NO = ( 2 mols N2 reacted ) ( 2 mol NO / mol N2 reacted )moles NO = 4 moles NOmass NO = ( 4 mol NO ) ( 30 g NO / mol NO ) = 120 g NO
How many grams of NaN3 are required to produce 13.0 ft3 of nitrogen gas if the gas has a density of 1.25 gL?
13.0 cubic feet is equivalent to .3681 cubic meters, which is equivalent to 368.1 liters. At 1.25 grams/liter, there are 460.1 grams. Nitrogen gas has a molar mass of 28.0134 g/mol, so there are 16.4 moles of N2. The equation for the decomposition of NaN3 is 2 NaN3 --> 2 Na + 3 N2. So, for every 3 moles of N2, there must have been 2 moles of NaN3, hence there was 10.9 moles. With a molar mass of 65.01 g/mol, there were 709 grams of NaNO3 to begin with.
If you start with twenty eight grams of nitrogen and six grams of hydrogen what is the mass of ammonia formed?
Mr(N2) = ~28gmol-1, Mr(H2) = ~2gmol-1. This means there is 1 mole of N2 and 3 moles of H2; this will react completely, so there will be 28 + 6 = 34 grams of ammonia (NH3).
How many grams of NH3 can be produced from 2.79 moles of N2?
The mass of ammonia will be 95,03 g.
How many grams are in 0.713 moles of Ga?
For this you need the atomic (molecular) mass of N2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel..713 moles × (69.7 grams) = 49.7 grams Ga
How many grams are in 2.25 moles of N2?
For this you need the atomic (molecular) mass of N2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.25 moles × 28.0 grams = 63.0 grams N2
How many moles of NH3 can be produced from 14 grams of N2?
The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
How many moles of N are there in 0.189 grams of N20?
The answer is 0,0043 moles of N2.
If the total mass of N2 in the atmosphere is 3.87e21 grams or 2.901 moles based on the denitrification rate of 310e12 grams year what is the residence time of N2 in the atmosphere?
Residence time = 3.87E21/310E12 = 1.25E7 years
How many grams of NH3 can be produced from 4.46 mol of N2 and excess H2.?
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
How many grams of NO are produced from the reaction of 2 mol of N2 with 2 mol of O2?
You have :N2 + O2 -----> 2NOmoles NO = ( 2 mols N2 reacted ) ( 2 mol NO / mol N2 reacted )moles NO = 4 moles NOmass NO = ( 4 mol NO ) ( 30 g NO / mol NO ) = 120 g NO
What mass of NH3 is produced when 1.20 mol of N2 react completely in the following equation N2 plus 3H2 2NH3?
N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3
How many grams of NaN3 are required to produce 13.0 ft3 of nitrogen gas if the gas has a density of 1.25 gL?
13.0 cubic feet is equivalent to .3681 cubic meters, which is equivalent to 368.1 liters. At 1.25 grams/liter, there are 460.1 grams. Nitrogen gas has a molar mass of 28.0134 g/mol, so there are 16.4 moles of N2. The equation for the decomposition of NaN3 is 2 NaN3 --> 2 Na + 3 N2. So, for every 3 moles of N2, there must have been 2 moles of NaN3, hence there was 10.9 moles. With a molar mass of 65.01 g/mol, there were 709 grams of NaNO3 to begin with.
If you start with twenty eight grams of nitrogen and six grams of hydrogen what is the mass of ammonia formed?
Mr(N2) = ~28gmol-1, Mr(H2) = ~2gmol-1. This means there is 1 mole of N2 and 3 moles of H2; this will react completely, so there will be 28 + 6 = 34 grams of ammonia (NH3).
Can be measured only by its effects on matter?
Give the number of moles of N2 in 70.05 g of N2, (molar mass of N2 = 28.02 g/mol)
