3.40 X 1022 atoms helium (1 mole He/6.022 X 1023)(4.003 grams/1 mole He)
= 0.226 grams
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There are approximately 6.023 x 10^23 atoms in 1 mole of any element, including argon. The molar mass of argon is approximately 40 grams/mol, so 22 grams of argon would contain about (6.023 x 10^23 atoms/mol) * (22 grams / 40 grams/mol) = 3.34 x 10^23 atoms of argon.
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AuCl3= 303.5 grams5.00 grams AuCl3 / (303.5 grams) × (6.02 × 1023 atoms) = 9.92 × 1021 atoms
17.48 atoms
There are about 2.56 x 10^22 atoms in 10 grams of gold. This calculation is based on the atomic mass of gold (197 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol).
To find this, you need to first calculate the molar mass of gold (Au), which is 196.97 g/mol. Next, you convert the given mass (5 grams) to moles by dividing by the molar mass. Then, you use Avogadro's number (6.022 x 10^23) to convert moles to atoms. In this case, there are approximately 6.022 x 10^22 atoms in 5 grams of gold.
The periodic table states that the molar mass of copper is 63.546 grams per mole. That means that if you have one mole of copper, it will weigh 63.546 grams. One mole is 6.022x1023 (Avogadro's number) atoms. To find the mass of one copper atom in grams, you simply divide copper's molar mass by the number of atoms in one mole. 63.546 / 6.022x1023 = 1.055x10-22 One atom of copper weighs 1.055x10-22 grams.
There are approximately 6.023 x 10^23 atoms in 1 mole of any element, including argon. The molar mass of argon is approximately 40 grams/mol, so 22 grams of argon would contain about (6.023 x 10^23 atoms/mol) * (22 grams / 40 grams/mol) = 3.34 x 10^23 atoms of argon.
Five iron atoms have a mass of 1.3155 x 10-22 grams.
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AuCl3= 303.5 grams5.00 grams AuCl3 / (303.5 grams) × (6.02 × 1023 atoms) = 9.92 × 1021 atoms
17.48 atoms
4.771 X 1022 atoms neodymium (1 mole Nd/6.022 X 1023)(144.2 grams/1 mole Nd) = 11.42 grams of neodymium --------------------------------------
There are about 2.56 x 10^22 atoms in 10 grams of gold. This calculation is based on the atomic mass of gold (197 g/mol) and Avogadro's number (6.022 x 10^23 atoms/mol).
To find this, you need to first calculate the molar mass of gold (Au), which is 196.97 g/mol. Next, you convert the given mass (5 grams) to moles by dividing by the molar mass. Then, you use Avogadro's number (6.022 x 10^23) to convert moles to atoms. In this case, there are approximately 6.022 x 10^22 atoms in 5 grams of gold.
There are 1.9 grams of Carbon. The molar mass of carbon is approximately 12 grams per mole. This means there are ~0.158 moles of carbon. Since 1 mole of carbon contains Avogadro's number of atoms (~6.022 x 10^23 atoms), then 0.158 moles would contain ~9.53 x 10^22 atoms.
To calculate the number of grams in 8.2x10^22 molecules of N2I6, you would need to determine the molar mass of N2I6. Once you have the molar mass, you can use it to convert the number of molecules to grams using Avogadro's number and the formula: mass = (number of molecules / Avogadro's number) x molar mass.
1 mole has 12.01 grams and has 6.022 x 1023 atoms. There are 6 carbon atoms in a glucose molecule so that times six would give you a total of 72.06 grams out of the 180.156 (molar mass for glucose). Carbon makes up about 40 percent of the total glucose mass so the final answer would be it would be around 2.4088 x 1023 atoms of carbon in one gram. Times that by 4 and you'll get 9.6352 x 1023 atoms of carbon in four gram of glucose.
To calculate the number of gold atoms in one kilogram, we first need to determine the number of atoms in 1 gram, then multiply by 1000 to account for the kilogram. Given that one atom of gold weighs 3.27x10^-22 grams, the number of atoms in 1 gram would be 1/(3.27x10^-22) = 3.06x10^21 atoms. Therefore, in one kilogram (1000 grams) of gold, there would be 3.06x10^24 atoms.