4.32 moles Barium (6.022 X 10^23/1 mole Ba)
= 2.60 X 10^24 atoms
The formula mass for barium chloride (BaCl2) can be calculated by adding the atomic masses of each element in the compound. The atomic mass of barium (Ba) is 137.33 g/mol, and the atomic mass of chlorine (Cl) is 35.45 g/mol. Therefore, the formula mass of barium chloride (BaCl2) is 137.33 + (2 * 35.45) = 208.23 g/mol.
The molar mass of BaSO4 (Barium sulfate) can be calculated by adding the molar mass of each element present in the formula: Ba (barium) has a molar mass of 137.33 g/mol, S (sulfur) has a molar mass of 32.06 g/mol, and O (oxygen) has a molar mass of 16.00 g/mol. Adding these together gives a molar mass of 137.33 + 32.06 + (4 * 16.00) = 233.37 g/mol for BaSO4.
The chemical formula of barium chloride is BaCl2.The molecular mass is 208,23 g (for the anhydrous salt).
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
233.43 g On A+ the answer's 233.4 =]
The chemical formula for Barium Hydride is BaH2. Ba = Barium H = Hydrogen Its molecular mass is 139.34288 g/mol.
The formula mass of Barium acetate (Ba(C2H3O2)2) is calculated by adding the atomic masses of each element in the compound. The atomic mass of Barium (Ba) is 137.33 g/mol, Carbon (C) is 12.01 g/mol, Hydrogen (H) is 1.01 g/mol, and Oxygen (O) is 16.00 g/mol. Therefore, the formula mass of Barium acetate is 255.4 g/mol.
The formula mass for barium chloride (BaCl2) can be calculated by adding the atomic masses of each element in the compound. The atomic mass of barium (Ba) is 137.33 g/mol, and the atomic mass of chlorine (Cl) is 35.45 g/mol. Therefore, the formula mass of barium chloride (BaCl2) is 137.33 + (2 * 35.45) = 208.23 g/mol.
The formula mass of barium fluoride (BaF2) is calculated by adding the atomic masses of each element in the compound. Barium has an atomic mass of 137.33 g/mol, and fluorine has an atomic mass of 18.998 g/mol. Multiplying the atomic mass of barium by 1 and the atomic mass of fluorine by 2 (because there are two fluorine atoms in the compound) and adding them together gives a formula mass of 175.33 g/mol.
The molar mass for anhydrous barium sulfate (BaSO4) is 233.43 g/mol
The molar mass of BaSO4 (Barium sulfate) can be calculated by adding the molar mass of each element present in the formula: Ba (barium) has a molar mass of 137.33 g/mol, S (sulfur) has a molar mass of 32.06 g/mol, and O (oxygen) has a molar mass of 16.00 g/mol. Adding these together gives a molar mass of 137.33 + 32.06 + (4 * 16.00) = 233.37 g/mol for BaSO4.
The chemical formula for Barium Hydride is BaH2. Ba = Barium H = Hydrogen Its molecular mass is 139.34288 g/mol.
The chemical formula of barium chloride is BaCl2.The molecular mass is 208,23 g (for the anhydrous salt).
get the volume of the chemical and the mass and divide the mass by it's volume
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
233.43 g On A+ the answer's 233.4 =]
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.