233.43 g
On A+ the answer's 233.4 =]
The molar mass of BaSO4 (Barium sulfate) can be calculated by adding the molar mass of each element present in the formula: Ba (barium) has a molar mass of 137.33 g/mol, S (sulfur) has a molar mass of 32.06 g/mol, and O (oxygen) has a molar mass of 16.00 g/mol. Adding these together gives a molar mass of 137.33 + 32.06 + (4 * 16.00) = 233.37 g/mol for BaSO4.
The molar mass of barium sulfate, BaSO4 is 233.4 Amount of BaSO4 = mass of sample / molar mass = 14.2/233.4 = 0.0608mol 0.0608 moles of BaSO4 are conained in a 14.2g pure sample.
The molar mass of iron(II) sulfate (FeSO4) is 151.91 g/mol.
The molar mass of chromic sulfate (Cr2(SO4)3) is approximately 392.15 g/mol.
To determine the mass of barium in barium phosphate, we need to know the molar ratio of barium to oxygen in the compound. If we assume a 1:3 ratio between barium and oxygen in barium phosphate (Ba3(PO4)2), we can calculate the molar mass of barium and oxygen in the compound. With this information, we can find the mass of barium in the sample by subtracting the mass of oxygen from the total mass.
The molar mass for anhydrous barium sulfate (BaSO4) is 233.43 g/mol
The molar mass of BaSO4 (Barium sulfate) can be calculated by adding the molar mass of each element present in the formula: Ba (barium) has a molar mass of 137.33 g/mol, S (sulfur) has a molar mass of 32.06 g/mol, and O (oxygen) has a molar mass of 16.00 g/mol. Adding these together gives a molar mass of 137.33 + 32.06 + (4 * 16.00) = 233.37 g/mol for BaSO4.
The molar mass of barium sulfate, BaSO4 is 233.4 Amount of BaSO4 = mass of sample / molar mass = 14.2/233.4 = 0.0608mol 0.0608 moles of BaSO4 are conained in a 14.2g pure sample.
To find the mass of barium sulfate produced, first calculate the moles of barium chloride and iron III sulfate using their volumes and concentrations. Then, determine the limiting reactant by comparing the moles of barium chloride and iron III sulfate and use it to find the moles of barium sulfate produced. Finally, multiply the moles of barium sulfate by its molar mass to find the mass in grams.
Since barium sulfate and barium chloride have a 1:1 molar ratio, you would need the same amount of barium chloride as barium sulfate, so 100 grams.
The molar mass of iron(II) sulfate (FeSO4) is 151.91 g/mol.
106
The molar mass of chromic sulfate (Cr2(SO4)3) is approximately 392.15 g/mol.
To determine the mass of barium in barium phosphate, we need to know the molar ratio of barium to oxygen in the compound. If we assume a 1:3 ratio between barium and oxygen in barium phosphate (Ba3(PO4)2), we can calculate the molar mass of barium and oxygen in the compound. With this information, we can find the mass of barium in the sample by subtracting the mass of oxygen from the total mass.
The molar mass of sulfate is 96.06 g/mol. Therefore, one mole of sulfate contains 96.06 grams of sulfate.
get the volume of the chemical and the mass and divide the mass by it's volume
342.15